Python3.6 BeautifulSoup无效
问题描述：
我的代码如下;
source_code = requests.get(kale_url_keys)
plain_text = source_code.text
soup = BeautifulSoup("plain_text ")
或
r = requests.get(kale_url_keys)
html = r.content
soup = BeautifulSoup(html, "html.parser")
我写下汤= BeautifulSoup（ANYTHING）时出错，如下所示;
I took error when I writing the "soup = BeautifulSoup(ANYTHING)" like below;
或
答
做两件事：
- 安装最新的稳定
Python 3.6.0 -
update
beautifulsoup4- 确保在正确的Python 3.6.0环境中更新它：
- install the latest stable
Python 3.6.0 update
beautifulsoup4- make sure you update it in the correct Python 3.6.0 environment:
pip3 install beautifulsoup4 --upgrade