one+two=3,该如何处理

one+two=3
这个题完全没有思路,不知道从哪里下手
先发下描述

Description
读入两个小于100 的正整数A 和B，计算A+B。需要注意的是：A 和B 的每一位数字
由对应的英文单词给出。
Input
测试输入包含若干测试用例，每个测试用例占一行，格式为"A + B ="，相邻两字符串有
一个空格间隔。当A 和B 同时为0 时输入结束，相应的结果不要输出。
Output
对每个测试用例输出1 行，即A+B 的值。
Sample Input
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
Sample Input
3
90
96

------解决方案--------------------
#include "stdio.h"
#include "string.h"

int swp(char a[10]);
int scan(void);
int main(int argc, char* argv[])
{
printf("input english number:\n");
int s1 = scan();
int s2 = scan();
printf("%d\n",s1+s2);
return 0;
}

int scan(void)
{
char a[10];
int g0,g1;
scanf("%s",a);
g0 = swp(a);
scanf("%s",a);
if((strcmp(a,"+")==0)||(strcmp(a,"=")==0))
{
return g0;
}
else
{
g1 = swp(a);
}
scanf("%s",a);
if((strcmp(a,"+")==0)||(strcmp(a,"=")==0))
{
return g0*10+g1;
}
}

int swp(char a[10])
{
int c;
if (strcmp(a,"zero")==0) c=0;
else if(strcmp(a,"one")==0) c=1;
else if(strcmp(a,"two")==0) c=2;
else if(strcmp(a,"three")==0) c=3;
else if(strcmp(a,"four")==0) c=4;
else if(strcmp(a,"five")==0) c=5;
else if(strcmp(a,"six")==0) c=6;
else if(strcmp(a,"seven")==0) c=7;
else if(strcmp(a,"eight")==0) c=8;
else if(strcmp(a,"nine")==0) c=9;
return c;
}
------解决方案--------------------
那我也来写一个吧：

C/C++ code

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string word;
    int i, a[2], b[2];
    int first, second, sum;
    while(1)
    {
        a[1] = a[2] = b[1] = b[2] = 10;
        i = 0;
        while(cin >> word)
        {
            if("zero" == word)
                a[i] = 0;
            if("one" == word) 
                a[i] = 1;
            else if("two" == word)
                a[i] = 2;
            else if("three" == word)
                a[i] = 3;
            else if("four" == word)
                a[i] = 4;
            else if("five" == word)
                a[i] = 5;
            else if("six" == word)
                a[i] = 6;
            else if("seven" == word)
                a[i] = 7;
            else if("eight" == word)
                a[i] = 8;
            else if("nine" == word)
                a[i] = 9;
            else if("+" == word)
                break;
            i++;
        }
        i = 0;
        while(cin >> word)
        {
            if("zero" == word)
                b[i] = 0;
            if("one" == word) 
                b[i] = 1;
            else if("two" == word)
                b[i] = 2;
            else if("three" == word)
                b[i] = 3;
            else if("four" == word)
                b[i] = 4;
            else if("five" == word)
                b[i] = 5;
            else if("six" == word)
                b[i] = 6;
            else if("seven" == word)
                b[i] = 7;
            else if("eight" == word)
                b[i] = 8;
            else if("nine" == word)
                b[i] = 9;
            else if("=" == word)
                break;
            i++;
        }
        if(10 == a[1])
            first = a[0];
        else
            first = a[0] * 10 + a[1];
        if(10 == b[1])
            second = b[0];
        else
            second = b[0] * 10 + b[1];
        sum = first + second;
        if(0 == sum)
            break;
        cout << sum << endl;
    }
    return 0;
}

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