指针问题......最后一天？ :-)

答

" mdh" < md ** @ comcast.netwrote in message

news：d8 **************************** ****** @ l17g2000 pri.googlegroups.com ...

"mdh" <md**@comcast.netwrote in message
news:d8**********************************@l17g2000 pri.googlegroups.com...

有一件事困扰了我一段时间（好吧，不止一件事！）。


如果我有一个功能：


foo（char * s）{

One thing has puzzled me a while ( well, more than one thing!).

If I have a function:

foo( char *s){

地址s的副本传递给foo。

A copy of the address s is passed to foo.

char * t = s;

char *t = s;

如果将复制的地址放入指针t，我们会存储一份副本。

We store a copy if the copied address into pointer t.

.....


s ++; < ---几次任意次

.....
s++; <<--- a few arbitrary times

我们将推送到函数中的地址的副本增加几个

时间。

We increment the copy of the address that was pushed into the function a few
times.

}


现在......我的问题是这个。


是t独立于s，意思是：


1）在s ++之后它还会指向s的开头吗？

}

Now...my question is this.

Is "t" independent of s, in the sense of:

1) Will it still point to the beginning of s, after s++ ?

当然。

Of course.

2）我想与1相关，如果我现在评估* t，它会成为s中的第一个

角色吗？

2) I guess related to 1, if I now evaluate *t, will it be the first
character in s?

我想K& R2第5章会有所帮助。

**发自 http://www.teranews.com **

I guess that K&R2 Chapter 5 will be helpful.
** Posted from http://www.teranews.com **

5月5日， 10:52 pm，mdh< m ... @ comcast.netwrote：

On May 5, 10:52 pm, mdh <m...@comcast.netwrote:

有一件事困扰了我一段时间（好吧，不止一件事！）。


如果我有一个功能：


foo（char * s）{


char * t = s;


.....


s ++; < ---几次任意时间


}


现在......我的问题是这个。


是t独立于s，意思是：


1）在s ++之后它仍然指向s的开头吗？


2）我想与1有关，如果我现在评价* t，它会是s中的第一个

字符吗？


谢谢......那是'它今天！

One thing has puzzled me a while ( well, more than one thing!).

If I have a function:

foo( char *s){

char *t = s;

.....

s++; <<--- a few arbitrary times

}

Now...my question is this.

Is "t" independent of s, in the sense of:

1) Will it still point to the beginning of s, after s++ ?

2) I guess related to 1, if I now evaluate *t, will it be the first
character in s?

Thanks...that''s it for today!!!

在尝试之前，有什么东西可以让你困惑

看看会发生什么？
>
-

Robert Gamble

How long does something have to puzzle you before you give it a try
and see what happens?

--
Robert Gamble

5月5日，7：59 * pm，Dann Corbit < dcor ... @ connx.comwrote：

On May 5, 7:59*pm, "Dann Corbit" <dcor...@connx.comwrote:

>

>

Ist独立于s，意思是：

Is "t" independent of s, in the sense of:

1）在s ++之后它还会指向s的开头吗？

1) Will it still point to the beginning of s, after s++ ?

当然。

Of course.

由于某种原因我有这个概念性概念，即当s增加时，它会导致t看到与s相同的原始数组部分。什么

你说的是，一旦新的指针被初始化，它会独立地运作
并可以这样使用？

For some reason I had this conceptual notion that as s is incremented,
it causes t to "see" the same part of the original array as s. What
you are saying is that once the new pointer is initialized, it acts
independently and can be used as such?

>