在具有透明背景的单色PNG图像上更改/覆盖颜色?
What I would like to be able to do is dynamically change a solid single-colored png to another color simply by inputting the desired color code without losing the transparent background. The implementations I've seen tend to be a bit sloppy, so I was wondering if anyone can give me advice on how they would implement it.
I'd be most comfortable with a PHP solution but Python works too, hell I'll even take a good canvas solution. Any advice/examples regarding this would be very much appreciated, thanks guys.
我希望能够通过输入动态地将纯色单色png动态更改为另一种颜色 所需的颜色代码,不会丢失透明背景。 我看到的实现往往有点草率,所以我想知道是否有人可以给我关于如何实现它的建议。 p>
我对PHP最熟悉 解决方案,但Python也工作,地狱我甚至会采取一个很好的画布解决方案。 关于这方面的任何建议/例子将非常感谢,谢谢你们。 p> div>
Ordinarily I like to work in the RGB color space, but this is a case where HLS works very well. The conversion in Python is simple, by replacing the H and S and leaving L the same.
import colorsys
from PIL import Image
def recolor(im, r, g, b):
h, l, s = colorsys.rgb_to_hls(r/255.0, g/255.0, b/255.0)
result = im.copy()
pix = result.load()
for y in range(result.size[1]):
for x in range(result.size[0]):
r2, g2, b2, a = pix[x, y]
h2, l2, s2 = colorsys.rgb_to_hls(r2/255.0, g2/255.0, b2/255.0)
r3, g3, b3 = colorsys.hls_to_rgb(h, l2, s)
pix[x, y] = (int(r3*255.99), int(g3*255.99), int(b3*255.99), a)
return result
recolor(im_flag, 255, 0, 0).save(r'c:\temped_flag.png')
Here's a simple canvas implementation:
colorize = function(image, r, g, b) {
var newImg = $('<canvas>')[0];
newImg.width = image.width;
newImg.height = image.height;
var newCtx = newImg.getContext('2d');
newCtx.drawImage(image, 0, 0);
var imageData = newCtx.getImageData(0, 0, image.width, image.height);
data = imageData.data;
for (var i = 0; i < data.length; i += 4) {
data[i+0] = r;
data[i+1] = g;
data[i+2] = b;
}
newCtx.putImageData(imageData, 0, 0);
return newImg;
};
JSFiddle: http://jsfiddle.net/bK7P9/6/
You can do this using PIL and numpy in Python. Assuming we have a method NewSolidImage
(which we'll define below), we can turn an image into an array of pixels, use the method to convert the pixels and then save to a new file:
import numpy
from PIL import Image
def CreateNewImage(current_filename, new_filename, new_color):
image = Image.open(current_filename)
image_values = numpy.array(image)
new_image_values = NewSolidImage(image_values, new_color)
new_image = Image.fromarray(new_image_values)
new_image.save(new_filename)
Now to define this method. We simply take an array, make sure it is the shape that we expect and then on pixels that aren't 100% transparent, we set the red, green, blue values to those of the solid passed in.
def NewSolidImage(rgba_array, new_color):
new_r, new_g, new_b = new_color
rows, cols, rgba_size = rgba_array.shape
if rgba_size != 4:
raise ValueError('Bad size')
for row in range(rows):
for col in range(cols):
pixel = rgba_array[row][col]
transparency = pixel[3]
if transparency != 0:
new_pixel = pixel.copy()
new_pixel[0] = new_r
new_pixel[1] = new_g
new_pixel[2] = new_b
rgba_array[row][col] = new_pixel
return rgba_array