Lucene数据储存结构中的VInt(可变长度整型)
转载自:
http://www.blogjava.net/persister/archive/2010/02/02/311642.html
A variable-length format for positive integers is defined where the high-order bit of each byte indicates whether more bytes remain to be read. The low-order seven bits are appended as increasingly more significant bits in the resulting integer value. Thus values from zero to 127 may be stored in a single byte, values from 128 to 16,383 may be stored in two bytes, and so on. 可变格式的整型定义:最高位表示是否还有字节要读取,低七位就是就是具体的有效位,添加到 结果数据中。比如00000001 最高位表示0,那么说明这个数就是一个字节表示,有效位是后面的七位0000001,值为1。10000010 00000001 第一个字节最高位为1,表示后面还有字节,第二位最高位0表示到此为止了,即就是两个字节,那么具体的值注意,是从最后一个字节的七位有效数放在最前面,依次放置,最后是第一个自己的七位有效位,所以这个数表示 0000001 0000010,换算成整数就是130 VInt Encoding Example Value First byte Second byte Third byte 0 00000000 1 00000001 2 00000010 ... 127 01111111 128 10000000 00000001 129 10000001 00000001 130 10000010 00000001 ... 16,383 11111111 01111111 16,384 10000000 10000000 00000001 16,385 10000001 10000000 00000001 ... Lucene源代码中进行存储和读取是这样的。OutputStream是负责写:
2 * five bytes. Smaller values take fewer bytes. Negative numbers are not
3 * supported.
4 * @see InputStream#readVInt()
5 */
6 public final void writeVInt(int i) throws IOException {
7 while ((i & ~0x7F) != 0) {
8 writeByte((byte)((i & 0x7f) | 0x80));
9 i >>>= 7;
10 }
11 writeByte((byte)i);
12 }
InputStream负责读:
2 * five bytes. Smaller values take fewer bytes. Negative numbers are not
3 * supported.
4 * @see OutputStream#writeVInt(int)
5 */
6 public final int readVInt() throws IOException {
7 byte b = readByte();
8 int i = b & 0x7F;
9 for (int shift = 7; (b & 0x80) != 0; shift += 7) {
10 b = readByte();
11 i |= (b & 0x7F) << shift;
12 }
13 return i;
14 }
>>>表示无符号右移