关于在VS2010停生成unsigned char[16] 的MD5码赋值给char[16]显示乱码

关于在VS2010下生成unsigned char[16] 的MD5码赋值给char[16]显示乱码
最近要写一个给已有文件添加一个头结构并保存为新文件的程序，在用网上的MD5类在VS2010下生成了unsigned char[16] mdContext.digst类型的MD5码，我的头结构里有个保存该值的char[16] fheader.md5，但是用strcpy(fheader.md5, (char*)mdContext.digst) 或者 strncpy(fheader.md5, (char*)mdContext.digst, 16)转换后 再赋给静态编辑框绑定的CString m_strMD5，显示为乱码，正常的应该是一串数字字母啊！搞了一天了，求大神解答，谢谢。 
是不是因为strcpy的时候unsigned char 转 char出问题了？但是别人VS2008写的同样的程序好像能正常显示啊....
------解决方案--------------------
调试看看fheader.md5和mdContext.digst的值就清楚了。
------解决方案--------------------

#include <stdio.h>

#include <math.h>

#include <string.h>

#include <memory.h>

const unsigned int s[4][4]={{7,12,17,22},{5,9,14,20},{4,11,16,23},{6,10,15,21}};

const unsigned long t[64]={//t[i]=4294967296*fabs(sin(i+1));

 0xd76aa478,0xe8c7b756,0x242070db,0xc1bdceee,0xf57c0faf,0x4787c62a,0xa8304613,0xfd469501,

 0x698098d8,0x8b44f7af,0xffff5bb1,0x895cd7be,0x6b901122,0xfd987193,0xa679438e,0x49b40821,

 0xf61e2562,0xc040b340,0x265e5a51,0xe9b6c7aa,0xd62f105d,0x02441453,0xd8a1e681,0xe7d3fbc8,

 0x21e1cde6,0xc33707d6,0xf4d50d87,0x455a14ed,0xa9e3e905,0xfcefa3f8,0x676f02d9,0x8d2a4c8a,

 0xfffa3942,0x8771f681,0x6d9d6122,0xfde5380c,0xa4beea44,0x4bdecfa9,0xf6bb4b60,0xbebfbc70,

 0x289b7ec6,0xeaa127fa,0xd4ef3085,0x04881d05,0xd9d4d039,0xe6db99e5,0x1fa27cf8,0xc4ac5665,

 0xf4292244,0x432aff97,0xab9423a7,0xfc93a039,0x655b59c3,0x8f0ccc92,0xffeff47d,0x85845dd1,

 0x6fa87e4f,0xfe2ce6e0,0xa3014314,0x4e0811a1,0xf7537e82,0xbd3af235,0x2ad7d2bb,0xeb86d391

};

const int serial[64]={

 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,

 1,6,11,0,5,10,15,4,9,14,3,8,13,2,7,12,

 5,8,11,14,1,4,7,10,13,0,3,6,9,12,15,2,

 0,7,14,5,12,3,10,1,8,15,6,13,4,11,2,9

};

void func(unsigned long& a,

          unsigned long b,

          unsigned long c,

          unsigned long d,

          unsigned long M,

          unsigned long t,

          int s,

          int turn) {

    unsigned long temp;

    switch(turn) {

    case 0:

        temp=(b&c)
------解决方案--------------------
((~b)&d);

        break;

    case 1:

        temp=(d&b)
------解决方案--------------------
((~d)&c);

        break;

    case 2:

        temp=b^c^d;

        break;

    case 3:

        temp=c^(b
------解决方案--------------------
(~d));

        break;

    }

    temp+=M+t+a;

    _asm {

        mov ecx,s

        rol temp,cl

    }

    a=b+temp;

}

void MD512(const unsigned long M[16],unsigned long hash[4]) {

    int i,j,index=0;

    for (i=0;i<4;i++)

        for (j=0;j<4;j++) {

            func(hash[0],hash[1],hash[2],hash[3],M[serial[index]],t[index],s[i][0],i);

            index++;

            func(hash[3],hash[0],hash[1],hash[2],M[serial[index]],t[index],s[i][1],i);

            index++;

            func(hash[2],hash[3],hash[0],hash[1],M[serial[index]],t[index],s[i][2],i);

            index++;

            func(hash[1],hash[2],hash[3],hash[0],M[serial[index]],t[index],s[i][3],i);