关于网宿厦门研发中心笔试的一道PV操作题：利用java中的多线程实现生产者与消费者的同步有关问题

关于网宿厦门研发中心笔试的一道PV操作题：利用java中的多线程实现生产者与消费者的同步问题

票据为同步资源：每一时刻资源池中仅存在一张可供使用的票据

public class Ticket {
private int ticket=-1;
synchronized public void setTicket(int ticket)//生产票据
{
	if(this.ticket!=-1)
		try {
			wait();
		} catch (InterruptedException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
	this.ticket=ticket;
	System.out.println("生产产品"+this.getClass().getName()+this.ticket);
	notify();
}
synchronized public void  getTicket()//消费票据
 {
	if(this.ticket==-1)
		try {
			wait();
		} catch (InterruptedException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		System.out.println("消费产品"+this.getClass().getName()+this.ticket);
   this.ticket=-1;
   notify();
}
}

生产者类通过调用同步资源的生产函数来实现产生票据

public class Product implements Runnable {
     public Ticket ticket;
     public Product(Ticket ticket)
     {
    	 this.ticket=ticket;
     }
	public void run() {
		// TODO Auto-generated method stub
          for(int i=0;i<10;i++)
          {
			ticket.setTicket(i);
		
	    }


}
}
消费者同样通过调用同步资源中的set函数来重新设置资源池
public class Consumer implements Runnable {
    public Ticket ticket;
    public Consumer(Ticket ticket)
    {
    	this.ticket=ticket;
    }
	public void run() {
		// TODO Auto-generated method stub
        for(int i=0;i<10;i++)
        {
		ticket.getTicket();
	
	    }

}
}
测试类
public class ThreadTest {
public static void main(String[] args)
{
	Ticket ticket=new Ticket();
	Product pro=new Product(ticket);
	Consumer con=new Consumer(ticket);
	Thread thread1=new Thread(pro);
	Thread thread2=new Thread(con);
	thread1.start();
	thread2.start();
}
}