//1.将所有区间按照左端点从小到大排序
//2.从前往后依次枚举每个区间
//首先选择能够覆盖左端点的区间当中右端点最靠右的端点
//在所有能覆盖start的区间当中,选择右端点最大的区间
//选完之后将start更新成右端点的最大值
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 100010;
int n;
struct Range {
int l, r;
bool operator< (const Range &W)const {
return l < W.l;
}
} range[N];
int main() {
int st, ed;
scanf("%d%d", &st, &ed);
scanf("%d", &n);
for (int i = 0; i < n; i ++ ) {
int l, r;
scanf("%d%d", &l, &r);
range[i] = {l, r};
}
sort(range, range + n);
int res = 0;
bool success = false;
for (int i = 0; i < n; i ++ ) {
int j = i, r = -2e9;
//找所有左端点在start左边的区间右端点最大值是多少
while (j < n && range[j].l <= st) {
r = max(r, range[j].r);
j ++ ;
}
if (r < st) {
res = -1;
break;
}
res ++ ;
if (r >= ed) {
success = true;
break;
}
st = r;
i = j - 1;
}
if (!success) res = -1;
printf("%d
", res);
return 0;
}