C语言怎么用正则表达式取"zxdd^$&%dssexingsdf"这字符串里面的"OK"

#include <iostream.h>
#include <stdio.h>

int main () 
{
    
    char str[] = "zxdd^$&%dssexing<OK>sdf"; 
    char buf[30] = { 0 } ;
    sscanf(str,"%*[^<]<%[^>]" ,buf);
    cout<<buf<<endl;
    return 0;
}

------解决方案--------------------

C/C++ code

sscanf("zxdd^$&%dssexing<OK>sdf","%*[^<]%*[<]%[^>]%*",s);

------解决方案--------------------
你想要什么啊，夹在一对尖括号中间的字符串？