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为什么这里只改变一个【关键词】或【语句位置】会导致结果异常，求解！

分类: IT文章 • 2024-05-22 11:48:12
为什么这里只改变一个【关键词】或【语句位置】会导致结果错误，求解！！！
这个是正确的代码（gcc编译器、Dev-C++编译环境）
C/C++ code

#include <stdio.h>
/*
Input:
10
move 9 onto 1
move 8 over 1
move 7 over 1
move 6 over 1
pile 8 over 6
pile 8 over 5
move 2 over 1
move 4 over 9
quit

*/

void moveAontoB( int a, int b ) { }
void moveAoverB( int a, int b ) { }
void pileAontoB( int a, int b ) { }
void pileAoverB( int a, int b ) { }


int main( )
{
    int n, i, j;//Read the value: n | P.s. [ 0, n - 1 ] | 1 <= n && n <= 24; i, j are for loop;
    
    scanf( "%d", &n );

    char TempString[ 5 ];
    short TempShort[ 2 ];

    while( 1 ) {
        scanf( "%s", TempString );
        //Keyword1: m(o)ve; p(i)le; q(u)it;
        //Keyword2: o(n)to; o(v)er;
        if( TempString[ 1 ] == 'o' ){//Judge it 1"move"
            scanf( "%d%s%d", &TempShort[ 0 ], TempString, &TempShort[ 1 ] );
            printf( "%d %s %d\n", TempShort[ 0 ], TempString, TempShort[ 1 ] );//TEST
            if( TempString[ 1 ] == 'n' ) moveAontoB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"onto"
            else if( TempString[ 1 ] == 'v' ) moveAoverB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"over"
            else { }
        }
        else if( TempString[ 1 ] == 'i' ){//Judge it 1"pile"
            scanf( "%d%s%d", &TempShort[ 0 ], TempString, &TempShort[ 1 ] );
            printf( "%d %s %d\n", TempShort[ 0 ], TempString, TempShort[ 1 ] );//TEST
            if( TempString[ 1 ] == 'n' ) pileAontoB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"onto"
            else if( TempString[ 1 ] == 'v' ) pileAoverB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"over"
            else { }
        }
        else if( TempString[ 1 ] == 'u' ) break;//Judge it 1"quit"
        else { }
    }

    //Output them
    for( i = 0; i < n; i ++ ) {
        printf( "%d:", i );
        for( j = 0; j < 1; j ++ ) {}
        printf( "\n" );
    }

    system( "PAUSE" );
}

运行结果：
10
move 9 onto 1
9 onto 1
move 8 over 1
8 over 1
move 7 over 1
7 over 1
move 6 over 1
6 over 1
pile 8 over 6
8 over 6
pile 8 over 5
8 over 5
move 2 over 1
2 over 1
move 4 over 9
4 over 9
quit
Press any key to continue . . .


注意看：main( )下面的第一行。
1.我若将它改为short型，则不能输出TempString，调试发现TempString = "\0\0on"
2.或者我将这整句话，保留int，移到main( )之外也会失败。


具体代码：
情况1
C/C++ code

#include <stdio.h>
/*
Input:
10
move 9 onto 1
move 8 over 1
move 7 over 1
move 6 over 1
pile 8 over 6
pile 8 over 5
move 2 over 1
move 4 over 9
quit

*/

void moveAontoB( int a, int b ) { }
void moveAoverB( int a, int b ) { }
void pileAontoB( int a, int b ) { }
void pileAoverB( int a, int b ) { }

int main( )
{
    short n, i, j;//Read the value: n | P.s. [ 0, n - 1 ] | 1 <= n && n <= 24; i, j are for loop;

    scanf( "%d", &n );

    char TempString[ 5 ];
    short TempShort[ 2 ];

    while( 1 ) {
        scanf( "%s", TempString );
        //Keyword1: m(o)ve; p(i)le; q(u)it;
        //Keyword2: o(n)to; o(v)er;
        if( TempString[ 1 ] == 'o' ){//Judge it 1"move"
            scanf( "%d%s%d", &TempShort[ 0 ], TempString, &TempShort[ 1 ] );
            printf( "%d %s %d\n", TempShort[ 0 ], TempString, TempShort[ 1 ] );//TEST
            if( TempString[ 1 ] == 'n' ) moveAontoB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"onto"
            else if( TempString[ 1 ] == 'v' ) moveAoverB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"over"
            else { }
        }
        else if( TempString[ 1 ] == 'i' ){//Judge it 1"pile"
            scanf( "%d%s%d", &TempShort[ 0 ], TempString, &TempShort[ 1 ] );
            printf( "%d %s %d\n", TempShort[ 0 ], TempString, TempShort[ 1 ] );//TEST
            if( TempString[ 1 ] == 'n' ) pileAontoB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"onto"
            else if( TempString[ 1 ] == 'v' ) pileAoverB( TempShort[ 0 ], TempShort[ 1 ] );//Judge it 2"over"
            else { }
        }
        else if( TempString[ 1 ] == 'u' ) break;//Judge it 1"quit"
        else { }
    }

    //Output them
    for( i = 0; i < n; i ++ ) {
        printf( "%d:", i );
        for( j = 0; j < 1; j ++ ) {}
        printf( "\n" );
    }

    system( "PAUSE" );
}

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