如何在绘图中对饼图进行子图绘制?
问题描述:
如何在"fig"中子图"pie1",使其位于第一个"位置.这就是我的做法,但无法解决
How can I subplot 'pie1' in 'fig', so it be located at 'the first' position. this is how I am doing it but it doesn't work out
import pandas as pd
import numpy as np
import seaborn as sns
import plotly.offline as pyp
import plotly.graph_objs as go
from plotly import tools
import plotly.plotly as py
from plotly.offline import iplot,init_notebook_mode
from IPython.core.display import HTML
import plotly.io
df1=pd.read_excel('file.xlsx',sheet_name='sheet1',index=False)
con_pivot=pd.pivot_table(con,index='Category',values=('Payment'),aggfunc='sum',margins=True,margins_name='Total')
fig = tools.make_subplots(rows=2, cols=2, subplot_titles=('The first','3','2','4'))
pie1=go.Pie(labels=con_pivot.index,values=con_pivot.values)
fig.append_trace(pie1,1,1)
pyo.plot(fig)
任何帮助帮助将不胜感激. 谢谢
Any help help will be appreciated. Thank you
答
使用plotly的make_subplots
函数实现并排饼图的方法如下(非常感谢@Oysiyl提供的输入数据) :
The way to achieve the side by side pie charts using the make_subplots
function from plotly would be the following (Many thanks to @Oysiyl for the input data):
from plotly.subplots import make_subplots
import plotly.graph_objects as go
from plotly.offline import plot
fig = make_subplots(rows=1, cols=2, specs=[[{"type": "pie"}, {"type": "pie"}]])
fig.add_trace(go.Pie(
values=[16, 15, 12, 6, 5, 4, 42],
labels=["US", "China", "European Union", "Russian Federation",
"Brazil", "India", "Rest of World"
],
domain=dict(x=[0, 0.5]),
name="GHG Emissions"),
row=1, col=1)
fig.add_trace(go.Pie(
values=[27, 11, 25, 8, 1, 3, 25],
labels=["US", "China", "European Union", "Russian Federation",
"Brazil", "India", "Rest of World"
],
domain=dict(x=[0.5, 1.0]),
name="CO2 Emissions"),
row=1, col=2)
plot(fig)