递归获取XML文件中的所有节点

<?xml version="1.0" encoding="UTF-8" ?>
<students>
    <student id="1" message="this is Num.1">
        <name>one</name>
        <age>1</age>
        <address>Beijing</address>
    </student>
    
    <student id="2" message="this is Num.2">
        <name>two</name>
        <age>2</age>
        <address>Shanghai</address>
    </student>
    
    <student id="3" message="this is Num.3">
        <name>three</name>
        <age>3</age>
        <address>Henan</address>
    </student>
</students>

package com.oracle.test;

import java.util.ArrayList;
import java.util.List;

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;
import com.oracle.pojo.Student;

public class Test {
    public static void main(String[] args) {
        
        List<Student> students=new ArrayList<Student>();
        //获取dom4j中解析对象
        SAXReader reader=new SAXReader();
        
        //读取pro.xml文件
        try {
            Document document=reader.read("./src/pro.xml");
            Element rootElement=document.getRootElement();
            List<Element> elements=rootElement.elements("student");
            getChildElement(rootElement);
        } catch (DocumentException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
    
    /*
     * 递归方法，获取所有节点
     */
    public static void  getChildElement(Element element) {
        System.out.println(element.getName());
        List<Element> elements=element.elements();
        if(element!=null){
            for (Element element2 : elements) {
                getChildElement(element2);
            }
        }
    }

}