C＋＋ 生手求解
C＋＋ 新手求解
*************************************************
1:Hito.exe
2:PointerSample.exe
Which ?
＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊
例如上面这个输入1执行Hito.exe ，输入2执行Pointer .exe,输入exit或者其他数字结束。
补充下面两个是写好的单个程序
和
------解决方案--------------------
本帖最后由 psp_66 于 2014-06-14 00:31:23 编辑
如何写一个下面的程序，把两个.exe放一个里面*************************************************
1:Hito.exe
2:PointerSample.exe
Which ?
＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊＊
例如上面这个输入1执行Hito.exe ，输入2执行Pointer .exe,输入exit或者其他数字结束。
补充下面两个是写好的单个程序
#include "Hito.h"
//Hito.cpp
// define include statment
#include <stdio.h>
#include <iostream>
#include <string>
using namespace std;
string name;
int yearsold;
//Define Class
class CHito
{
private:
char m_name[40];
int m_age;
public:
void setname(char* ss)
{
strcpy(m_name,ss);
}
void setage(int tosi)
{
if(tosi<0) m_age=0; else m_age=tosi;
}
void disp()
{
cout << "name：" << m_name << endl;
cout << "age：" << m_age << endl;
}
};
void hitodispyamada()
{
CHito yamada;
yamada.setname("AA");
yamada.setage(30);
yamada.disp();
}
void hitodispyamamoto()
{
CHito yamamoto;
yamamoto.setname("BB");
yamamoto.setage(50);
yamamoto.disp();
}
//start here.
int main(void)
{
hitodispyamada();
hitodispyamamoto();
cout << endl;
return 0;
}
和
// PointerSample.cpp
#include <iostream>
using namespace std;
void AddressSample()
{
int x = 3;
cout << "ｘ " << x << endl;
cout << " ｘ " << &x << endl;
}void PointerSample()
{
int x = 4;
int* p;
p = &x;
cout << " ｘ " << x << endl;
cout << " ｘ " << p << endl;
}
void PointerSample3()
{
int x = 3,y = 4;
int* p1;
int* p2;
p1 = &x;
p2 = &y;
cout << " ｘ " << p1 << endl;
cout << " ｐ1 " << *p1 << endl;
cout << " ｘ " << p2 << endl;
cout << " ｐ2 " << *p2 << endl;
}
int main()
{
AddressSample();
PointerSample();
PointerSample3();
cout << endl;
return 0;
}
------解决方案--------------------
int main()
{
string s;
while (s != "2")
{
cout << endl;
cout << "*************************************************\n"
" 1:Hito\n"
" 2:PointerSample\n"
"Which ? ";
cin >> s;
if (s == "1")
{
run("./Hito");
}
else if (s == "2")
{
run("./Point");
}
}
return 0;
}