sql做连续减法怎么处理
sql做连续减法怎么办？
------解决方案--------------------
你的第二段Code， as totaldinner 后多了一个 减号， 去掉再试试。
- SQL code
(isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='04' and cq_ctime<=:etime),0) - isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='03' and cq_ctime<=:etime),0) ) as totaldinner //通过 (isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='04' and cq_ctime<=:etime),0) - isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='05' and cq_ctime<=:etime),0) - isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='03' and cq_ctime<=:etime),0) ) as totaldinner- //通不过
------解决方案--------------------
你的第二段Code， as totaldinner 后多了一个 减号， 去掉再试试。