C# access2010新建表报错。求解。

C# access2010新建表出错。。求解。。
RT，建立2个表studentid（id（pk），email，snippet，fname，attachmentpath） 和stuemail（email（pk），sname）

运行到这一步时，老时提示错误。。。求解

  Catalog cat = new Catalog();

                //string accesscon = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + datapath;

                cat.Create("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + datapath+";");

               //conn = new OleDbConnection();

                //conn.Open(accesscon,null,null,-1);

                Table studentid = new Table();

                studentid.ParentCatalog = cat;

                studentid.Name = "studentid";

                Column col = new Column();   //新增id字段

                col.ParentCatalog = cat;

                col.Type = DataTypeEnum.adVarChar;

                col.Name = "id";

                //col.Properties["AutoIncrement"].Value = false;

                studentid.Columns.Append(col, DataTypeEnum.adVarChar, 100);




                Column col1 = new Column();   

                col1.ParentCatalog = cat;

                col1.Type = DataTypeEnum.adVarChar;

                col1.Name = "snippet";

                studentid.Columns.Append(col1, DataTypeEnum.adVarChar, 200);



                Column col2 = new Column();   

                col2.ParentCatalog = cat;

                col2.Type = DataTypeEnum.adVarChar;

                col2.Name = "email";

                studentid.Columns.Append(col2, DataTypeEnum.adVarChar, 100);


                Column col3 = new Column();   

                col3.ParentCatalog = cat;

                col3.Type = DataTypeEnum.adVarChar;

                col3.Name = "fname";

                studentid.Columns.Append(col3, DataTypeEnum.adVarChar, 100);



                Column col4 = new Column();  

                col4.ParentCatalog = cat;

                col4.Type = DataTypeEnum.adVarChar;

                col4.Name = "attachmentpath";

                studentid.Columns.Append(col4, DataTypeEnum.adVarChar, 200);


                studentid.Keys.Append("PrimaryKey", KeyTypeEnum.adKeyPrimary, "id","","");

                cat.Tables.Append(studentid);

                System.Runtime.InteropServices.Marshal.ReleaseComObject(studentid);

              //  System.Runtime.InteropServices.Marshal.ReleaseComObject(cat);

                studentid = null;