asp.net使用jqgrid的编者、增加、删除功能完成后客户端如和判断服务器端处理是否成功
asp.net使用jqgrid的编辑、增加、删除功能完成后客户端如和判断服务器端处理是否成功
asp.net服务器端的处理后，如何返回个客户端成功与否信息？
谢谢
------解决方案--------------------
添加afterSubmit事件通过ajax对象获取返回值进行判断就行了
asp.net服务器端的处理后，如何返回个客户端成功与否信息？
谢谢
------解决方案--------------------
添加afterSubmit事件通过ajax对象获取返回值进行判断就行了
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<link href="css/jquery-ui-1.8.2.custom.css" rel="stylesheet" type="text/css" />
<link href="css/ui.jqgrid.css" rel="stylesheet" type="text/css" />
<script src="js/jquery.js" type="text/javascript"> </script>
<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"> </script>
<script type="text/javascript">
$(document).ready(function () {
$("#list4").jqGrid({
url: "read.ashx",
datatype: "json",
editurl: "save.ashx",//////保存路径
mtype: 'get',
height: 300,
colNames: ['编号', '姓名', '日期', '地点'],
autowidth: false, //自动设置宽度
rownumbers: true,
closeAfterSearch: true,
colModel: [{ name: "id", index: "id", sorttype: "int", width: 60, editable: false, search: true },
{ name: "xm", index: "xm", sorttype: "text", width: 100, search: true, editable: true },
{ name: "rq", index: "rq", sorttype: "text", width: 100, editable: true, search: true },
{ name: "dd", index: "dd", sorttype: "text", width: 150, editable: true, search: true }
],
sortname: 'ID',
sortorder: "asc",
viewrecords: true,
rowNum: 10,
rowList: [10, 20, 30],
pager: '#pager', pgbuttons: false, pginput: false, pgtext: false,
caption: "列表",
jsonReader: { root: 'list',
repeatitems: false
},
gridview: true,
edit: { bSubmit: '修改' }
});
jQuery("#list4").jqGrid('navGrid', '#pager',
{ add: true, addtext: 'aaadd', edit: true, del: true, search: true, refresh: true, navkeys: [true, 38, 40] },
{ afterSubmit: function (response, postdata) {
var res = response.responseText, ok = response.responseText == 'editok';
return [ok, ok ? '' : '修改发生错误鸟！'];
}, closeAfterEdit: true//配置这个通过afterSubmit返回的数据是否关闭，成功则关闭，否则提示错误
},
{ afterSubmit: function (response, postdata) {
var res = response.responseText, ok = response.responseText == 'addok';
return [ok, ok ? '' : '添加数据发生错误鸟！'];