用java写有着意思的玩意，你会吗,该怎么解决

    public static void main(String[] args) {
        int m = 6;/*行*/
        int n = 6;/*列*/
        int[][] pos = new int[m][n];/*位置*/
        /**
         * 位置结构如下：
         * [0][0],[0][1],[0][2],[0][3],[0][4]
         * 
         * [1][0],[1][1],[1][2],[1][3],[1][4]
         * 
         * [2][0],[2][1],[2][2],[2][3],[2][4]
         * 
         * [3][0],[3][1],[3][2],[3][3],[3][4]
         * 
         * [4][0],[4][1],[4][2],[4][3],[4][4]
         */
        int count = 0;
        int r = 0, c = 0;/*r:行下标    l:列下标    pos[r][l]对应以上位置*/
        /*赋值方向，先向右c++，再向下r++，再向左c--，再向上r--*/
        final int up = 1;
        final int  down = -1;
        final int left = 2;
        final int right = -2;
        int dir = right;/*开始方向*/
        int cir = 1;/* 第几圈赋值 */
        while(true){
            count++;
            pos[r][c]=count;/*赋值*/
            switch(dir){
                case right:
                    if(c<n-cir){/*当前行右方还有没赋值的*/
                        c++;
                    }else{
                        dir = down;
                        r++;
                    }
                    break;
                case down:
                    if(r<m-cir){/*当前列下方还有没赋值的*/
                        r++;
                    }else{
                        dir = left;
                        c--;
                    }
                    break;
                case left:
                    if(c>cir-1){/*当前行左边还有没赋值的*/
                        c--;
                    }else{
                        dir = up;
                        r--;
                    }
                    break;
                case up:
                    if(r>cir){/*当前列上边边还有没赋值的*/
                        r--;
                    }else{
                        cir++;/*赋值了一圈*/
                        dir = right;
                        c++;
                    }
                    break;
            }
            if(count>=m*n){
                break;
            }
        }
        /*输出回数*/
        for(int i = 0; i<m; i++){
            for(int j = 0; j<n; j++){
                if(pos[i][j]<10){
                    System.out.print(pos[i][j]+" "+" ");
                }else{
                    System.out.print(pos[i][j]+" ");
                }
            }
            System.out.println();
        }
    }

------解决方案--------------------

Java code

public class SpiralMatrix {

    public final static int DOWN_FIRST = 0;
    public final static int RIGHT_FIRST = 1;

    public static void main(String[] args) {
        int[][] spiralMatrix = spiralMatrix(5, RIGHT_FIRST);
        output(spiralMatrix);
    }
    
    public static int[][] spiralMatrix(final int side, final int direction) {
        int[][] matrix = new int[side][side];
        int[] rc = { 0, 0 };
        int c = 0, n = 1, t = (side << 1) - 1;
        while(c < t) {
            int p = (c + 1) >> 1;
            while(p++ < side) {
                matrix[rc[0]][rc[1]] = n++;
                if(p == side) {
                    c++;
                }
                rc[(c & 1) ^ direction] += 1 - (c & 2);
            }
        }
        return matrix;
    }

    private static void output(int[][] matrix) {
        for(int i = 0; i < matrix.length; i++) {
            for(int j = 0; j < matrix[i].length; j++) {
                if(j > 0) {
                    System.out.print(' ');
                }
                System.out.printf("%2d", matrix[i][j]);
            }
            System.out.println();
        }
    }
}