android访问netbeans开发的java webservice,该如何处理

android访问netbeans开发的java webservice
用netbeans开发的webservice服务,地址:http://localhost:8082/WebService/MyTestService?tester,可以看到测试界面,输入参数后正常返回,并看到soap请求和响应的xml格式:

SOAP 请求

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<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Header/>
    <S:Body>
        <ns2:add xmlns:ns2="http://service/">
            <num1>3</num1>
            <num2>4</num2>
        </ns2:add>
    </S:Body>
</S:Envelope>


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SOAP 响应

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<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Body>
        <ns2:addResponse xmlns:ns2="http://service/">
            <return>7</return>
        </ns2:addResponse>
    </S:Body>
</S:Envelope>


我在android程序里:

InputStream inStream; 
inStream = getAssets().open("test.xml");
String soap = readSoapFile(inStream, num1,num2);  
byte[] data = soap.getBytes();  
// 提交Post请求   
URL url = new URL("http://10.93.136.5:8082/WebService/MyTestService");  
HttpURLConnection conn = (HttpURLConnection) url.openConnection();  
conn.setRequestMethod("POST");  
conn.setConnectTimeout(5 * 1000);  
conn.setDoOutput(true);  
conn.setRequestProperty("Content-Type", "application/soap+xml; charset=utf-8");  
conn.setRequestProperty("Content-Length", String.valueOf(data.length));  
OutputStream outStream = conn.getOutputStream();  
outStream.write(data);  
outStream.flush();  
outStream.close();  
if (conn.getResponseCode() == 200)  
 {  
     // 解析返回信息   
     return parseResponseXML(conn.getInputStream());  
 } 
 
private String readSoapFile(InputStream inStream, String num1, String num2) throws Exception  
{                                                                                        
    // 从流中获取文件信息                                                                
    byte[] data = readInputStream(inStream);                                             
    String soapxml = new String(data);                                                   
    // 占位符参数                                                                        
    Map<String, String> params = new HashMap<String, String>();                          
    params.put("param1", num1);