从多维数组中求和并合并重复值
问题描述:
I would like to sum the value of movements
while keeping an unique value for day
on the same array.
The base array:
array (607)
0 => array (2)
day => "11" (2)
movements => 1
1 => array (2)
day => "11" (2)
movements => 1
2 => array (2)
day => "11" (2)
movements => 1
3 => array (2)
day => "12" (2)
movements => 1
4 => array (2)
day => "12" (2)
movements => 1
5 => array (2)
day => "12" (2)
movements => 1
[...]
The result I am expecting (for each day
sum movements
):
array (607)
0 => array (2)
day => "11" (2)
movements => 3
1 => array (2)
day => "12" (2)
movements => 3
[...]
Any help would be greatly appreciated.
Edit: What I have tried so far :
-
sum-array-values-of-the-same-key: it also sum
day
which is not what I am expecting. -
my own code:
$arr1 = $stats['data']['vhc']; // contain ['day'] and ['movements'] $arr2 = $data['vhc']; // contain ['day'] and ['movements'] $sum = []; if (!empty($arr1)) { $result = []; foreach ($arr1 as $key => $value) { if (isset($arr2[$key]['day']) && $arr2[$key]['day'] == $value['day']) { $result['day'] = $value['day']; $result['movements'] = $value['movements'] + $arr2[$key]['movements']; } array_push($sum, $result); } }
答
You can easily do with foreach()
and array_values()
$final_array = [];
foreach($array as $arr){
$final_array[$arr['day']]['day'] = $arr['day'];
$final_array[$arr['day']]['movements'] = (isset($final_array[$arr['day']]['movements']))? $final_array[$arr['day']]['movements']+$arr['movements'] : $arr['movements'];
}
$final_array = array_values($final_array);
print_r($final_array);
Output:-https://eval.in/957326
答
This method will not bother overwriting result array data with the same value.
Code: (Demo)
$array=[
['day'=>'11','movements'=>'1'],
['day'=>'11','movements'=>'1'],
['day'=>'11','movements'=>'1'],
['day'=>'12','movements'=>'1'],
['day'=>'12','movements'=>'1'],
['day'=>'12','movements'=>'1']
];
foreach($array as $row){ // iterate all rows
if(!isset($result[$row['day']])){ // if first occurrence of day...
$result[$row['day']]=$row; // save the full row with day as the temporary key
}else{ // if not the first occurrence of day...
$result[$row['day']]['movements']+=$row['movements']; // add movements value
}
}
var_export(array_values($result));
Output:
array (
0 =>
array (
'day' => '11',
'movements' => 3,
),
1 =>
array (
'day' => '12',
'movements' => 3,
),
)