关于C++的一个简单有关问题

关于C++的一个简单问题
在这里先给大家拜个晚年,祝大家新年里工作顺利,幸福安康!

题目:   某运输公司对用户计算运费:设每千米每吨货物的基本运费为price,货位重为weight,距离为distance,折扣为discount,则总运费frieght的计算公式:
                                fright=price*distance*(1-discount)
其中,distance的折扣标准如下:
distance <250km               没有折扣
250 <=distance <500         2%折扣
500 <=diatance <1000       5%
1000 <=distance <2000     8%
2000 <=distance <3000     10%
3000 <=distance               15%
试编写程序,输入price,weight和distance,计算总运费freight.

#include   "stdafx.h "
#include   <iostream>

using   namespace   std;

void   main()
{
long   int   distance;
double   price,   weight,   discount;
double   freight;

cout < < "price " < <endl;
cin> > price;
cout < < "weight " < <endl;
cin> > weight;
cout < < "distance " < <endl;
cin> > distance;



if(distance <250)
discount=0;
else   if(distance <500)
discount=2%;
else   if(distance <1000)
discount=5%;
else   if(distance <2000)
discount=8%;
else   if(distance <3000)
discount=10%;
else   if(distance> =3000)
discount=15%;

freight=price*weight*distance*(1-discount);
cout < < "freight= " < <freight < <endl;

}

不知我这样编哪里错了,还有如果用switch-case写怎么写

------解决方案--------------------
个人觉得你去题目理解有误
觉得该是那种个人所得税的算法
#include "stdafx.h "
#include <iostream>

using namespace std;

void main()
{
long int distance;
double price, weight, discount;
double freight;

cout < < "price " < <endl;
cin> > price;
cout < < "weight " < <endl;
cin> > weight;
cout < < "distance " < <endl;
cin> > distance;


if(distance <250)
freight=distance*weight*1*price
else if(distance <500)
freight=250*weight*price+distance*(distance-250)*price*0.98
......

freight=price*weight*distance*(1-discount);
cout < < "freight= " < <freight < <endl;

}

这里switch (parseInt(distance / 250))
case 0:....break;
case 1:....break;
....
default:....

------解决方案--------------------
else if(distance <500)
discount=2%;//改为 discount=0.02
else if(distance <1000)
discount=5%;// 0.05
else if(distance <2000)
discount=8%;// 0.08
else if(distance <3000)
discount=10%; // 0.1
else if(distance> =3000)
discount=15%;//0.15

将上边的百分比斜位小数就可以通过编译了

------解决方案--------------------
楼主还有什么不明白，没有百分比类型，只有浮点型，楼上都已经改好了