如何从mysql中的表中选择N条记录

如何从mysql中的表中选择N条记录

问题描述:

如何从一个包含1000多个记录的表中仅获取10条记录.我有一个包含rowid,名称,成本的测试表.

How can I get only 10 records from a table where there are more than 1000 records. I have a test table with rowid, name, cost.

   select  name, cost from test;

在这里,我只想选择前10行,而不要选择rowid.

here I want to select only first 10 rows and dont want to select rowid.

要选择前十条记录,可以使用LIMIT,然后使用所需的记录数:

To select the first ten records you can use LIMIT followed by the number of records you need:

SELECT name, cost FROM test LIMIT 10

要从特定位置选择十条记录,可以使用LIMIT 10,100

To select ten records from a specific location, you can use LIMIT 10, 100

SELECT name, cost FROM test LIMIT 100, 10

这将显示记录101-110

This will display records 101-110

SELECT name, cost FROM test LIMIT 10, 100

这将显示记录11-111

This will display records 11-111

要确保您检索到正确的结果,请确保也对结果进行ORDER BY,否则返回的行可能是随机的

To make sure you retrieve the correct results, make sure you ORDER BY the results too, otherwise the returned rows may be random-ish

您可以阅读更多@ @ http://php.about.com/od /mysqlcommands/g/Limit_sql.htm

You can read more @ http://php.about.com/od/mysqlcommands/g/Limit_sql.htm