如何检查数组是否包含PHP中的另一个数组？

问题描述：

I would have a rather simple question today. We have the following resource:

$a = array(1 => 5, 2 => 3, 3 => 13, 9 => array('test'), 4 => 32, 5 => 33);

How is it actually possible to find out if array "a" has an array element in it and return the key if there is one (or more)?

今天我会有一个相当简单的问题。我们有以下资源： p>

  $ a = array（1 =＆gt; 5,2 =＆gt; 3 = 3 =＆gt; 13,9 =＆gt; array（'  test'），4 =＆gt; 32,5 =＆gt; 33）; 
  code>  pre> 
 
 如何确定数组“a”是否有数组？ 其中的元素，如果有一个（或更多），则返回密钥？ p> 
  div>

答

One possible approach:

function look_for_array(array $test_var) {
  foreach ($test_var as $key => $el) {
    if (is_array($el)) {
      return $key;
    }
  }
  return null;
}

It's rather trivial to convert this function into collecting all such keys:

function look_for_all_arrays(array $test_var) {
  $keys = [];
  foreach ($test_var as $key => $el) {
    if (is_array($el)) {
      $keys[] = $key;
    }
  }
  return $keys;
}

Demo.

答

You can use foreach since you are looking for any array:

foreach ($a as $key => $test) {
    if (is_array($test)) {
        $keys[] = $key;
    }
}

All keys of arrays for the array $a will be in the array $keys.

答

 $array = array(1 => 5, 2 => 3, 3 => 13, 9 => array('test'), 4 => 32, 5 => 33);
 foreach($array as $key => $value){
   if(is_Array($value)){
      echo $value[key($value)];
   }
 }

答

I have tried in different way.

$a = array(1 => 5, 2 => 3, 3 => 13, 9 => array('test'), 4 => 32, 5 => 33);

foreach ( $a as $aas  ):

        if(is_array($aas)){
            foreach ($aas as $key => $value):
                echo " (child array is this $key : $value)";
        endforeach;
        }else{
                echo " Value of array a = $aas : ";


        }
  endforeach;

output is like :

  Value of array a = 5 : Value of array a = 3 :
 Value of array a = 13 : (child array is this 0 :
 test) Value of array a = 32 : Value of array a = 33 :

如何检查数组是否包含PHP中的另一个数组？

相关推荐