linux下字符串存储的有关问题

linux下字符串存储的问题
char A[5];
int b = 1234;

如何保存使A[0] = 34
A[1] = 12
A[2] = 00
A[3] = 00
A[4] = 00

即 A[5] = "3412000000";

我保存后总是“D204000000”，郁闷哪，求救，谢谢各位

------解决方案--------------------
仅供参考

C/C++ code

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
unsigned int iv,i;
unsigned char BCD[5];//定长10位BCD码
unsigned char sv[11];
void main() {
    iv=123456789;//最大10位无符号正整数
    //INT2BCD
    sprintf(sv,"%010u",iv);
    for (i=0;i<10;i+=2) {
        BCD[i/2]=(sv[i]<<4)|(sv[i+1]&0x0F);
    }
    printf("BCD=%02x%02x%02x%02x%02x\n",BCD[0],BCD[1],BCD[2],BCD[3],BCD[4]);
    //BCD2INT
    for (i=0;i<10;i+=2) {
        sv[i]='0'|(BCD[i/2]>>4);
        sv[i+1]='0'|(BCD[i/2]&0x0F);
    }
    sscanf(sv,"%010u",&iv);
    printf("iv=%010u\n",iv);
    getch();
}

linux下字符串存储的有关问题

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