A + B Again 2057 有符号的64进位的运算
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output
0
2C
11
-2C
-90
Author
linle
Source
Recommend
1 #include<stdio.h> 2 int main() 3 { 4 long long int x,y,z; 5 while(~scanf("%llx%llx",&x,&y)) 6 { 7 (x+y>=0)?printf("%llX ",x+y):printf("-%llX ",-(x+y)); 8 } 9 return 0; 10 }