传递斯卡拉选项[列表[_]],用statement.setArray的Java JDBC阵列()
我试图建立从斯卡拉JDBC CallableStatements中的接口。在大多数情况下,它的简单,除了列表
。
I'm trying to build an interface from Scala to JDBC callableStatements. For the most part, it's straightforward, except for Lists
.
我需要能够采取一些类型的斯卡拉列表
,并将其转换成可以传递到语句的Java数组。 setArray(类型,数组)
和我没有任何运气(部分原因是因为我不知道Java和JDBC非常好)。
I need to be able to take a Scala List
of some type, and convert it into a Java Array that can be passed to statement.setArray(type, array)
and I'm not having any luck (partly because I don't know Java and JDBC very well).
下面就是我想要做的:
for (parameter <- ps.parameters) {
case GPArrayIn(None, t) => callableStatement.setNull(index, t)
case GPIn(v: Some[_], Types.INTEGER) => callableStatement.setInt(index, v.get.asInstanceOf[Int])
case GPIn(v: Some[_], Types.VARCHAR | Types.LONGVARCHAR) => callableStatement.setString(index, v.get.asInstanceOf[String])
case GPArrayIn(v: Some[List[_]], Types.INTEGER) => callableStatement.setArray(Types.INTEGER, ???? )
case GPArrayIn(v: Some[List[_]], Types.VARCHAR | Types.LONGVARCHAR) => callableStatement.setArray(Types.VARCHAR, ???? )
...
这是pretty直白简单的值,但是当涉及到 setArray()
呼叫我卡住了。
任何意见将是非常美联社preciated。一直停留在本作的小时... 的
Any advice would be sorely appreciated. Been stuck on this for hours...
setArray
需要了java.sql.Array
作为 DOC :
void setArray(int parameterIndex, Array x)
throws SQLException
您可以创建一个有:
sqlArray = connection.createArrayOf("VARCHAR", regularJavaArray);
这是类型:
Array createArrayOf(String typeName, Object[] elements)
throws SQLException
如果需要请参见这文档的实例和解释。
See this doc for examples and explanation if needed.
底线:你需要收集斯卡拉转换成Java数组,如果它不是已经是一个数组,然后将其转换Java数组到SQL阵列使用 createArrayOf
。它会做一些神奇的引擎盖下的映射数据,SQL ARRAY。
Bottom line: you need to convert Scala collection to java array if it's not an array already, then convert that Java array to SQL array using createArrayOf
. It will do some under the hood magic to map that data to SQL ARRAY.
对于模式匹配和提取,可以使用这样的事情:
As for the pattern matching and extraction, you can use something like that:
scala> val numbers = Array(1, 2, 3, 4)
numbers: Array[Int] = Array(1, 2, 3, 4)
scala> def arrayMatcher[T](maybeArray: Option[Array[T]]): String =
| maybeArray match {
| case Some(a: Array[Int]) => a.mkString(",")
| case Some(b: Array[String]) => b.mkString("-")
| case None => "no array"
| case _ => "no match"
| }
arrayMatcher: [T](maybeArray: Option[Array[T]])String
scala> arrayMatcher(Some(numbers))
res0: String = 1,2,3,4
scala> arrayMatcher(None)
res1: String = no array
scala> arrayMatcher(Some(numbers map(_.toString)))
res2: String = 1-2-3-4
scala> arrayMatcher(Some(Array(1.2, 3.4)))
res3: String = no match
scala> arrayMatcher(Some(List(1, 2)))
<console>:9: error: type mismatch;
found : Some[List[Int]]
required: Option[Array[?]]
arrayMatcher(Some(List(1, 2)))
^
要列表转换到阵列中使用:
To convert a list to array use:
scala> List(1, 2, 3).toArray
res6: Array[Int] = Array(1, 2, 3)