Ajax PHP表单按钮[重复]

问题描述：

This question already has an answer here:

Reference - What does this error mean in PHP? 34 answers

Can anyone tell me what I am missing here please?

Here is the basic HTML file with a simple "Create" and "Destroy" button that will eventually call an API. The button click with Ajax seems to work, but the PHP function is not being called.

testapi.html

<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
    $('.button').click(function(){
        var clickBtnValue = $(this).val();
        var ajaxurl = 'ajax.php',
        data =  {'action': clickBtnValue};
        $.post(ajaxurl, data, function (response) {
            alert("Action performed successfully!");
        });
    });

});
</script>
</head>
<body>
    <input type="submit" class="button" name="create" value="Create" />
    <input type="submit" class="button" name="destroy" value="Destroy" />
</body>
</html>

ajax.php

if (isset($_POST['action'])) {
    switch ($_POST['action']) {
        case 'create':
            create();
            break;
        case 'destroy':
            destroy();
            break;
    }
}
function create() {
    echo "Create function.";
    exit;
}
function destroy() {
    echo "Destroy function.";
    exit;
}

</div>

此问题已经存在这里有一个答案： p>

参考 - 这个错误在PHP中意味着什么？ 34答案 \ n span> li> ul> div>

有人能告诉我这里缺少什么吗？ p >

这是基本的HTML文件，其中包含一个简单的“创建”和“销毁”按钮，最终将调用API。使用Ajax单击按钮似乎有效，但PHP函数未被调用。 p>

testapi.html em> strong> p>

 ＆lt; html＆gt; 
＆lt; head＆gt; 
＆lt; script src =“https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min。  js“＆gt;＆lt; / script＆gt; 
＆lt; script＆gt; 
 $（document）.ready（function（）{
 $（'。button'）。click（function（）{
 var clickBtnValue = $（ 这个）.val（）; 
 var ajaxurl ='ajax.php'，
 data = {'action'：clickBtnValue}; 
 $ .post（ajaxurl，data，function（response）{
 alert（“ 动作成功执行！“）; 
}）; 
}）; 
 
}）; 
＆lt; / script＆gt; 
＆lt; / head＆gt; 
＆lt; body＆gt; 
＆lt; input type =”submit  “class =”button“name =”create“value =”Create“/＆gt; 
＆lt; input type =”submit“class =”button“name =”destroy“value =”Destroy“/＆gt; 
＆lt;  /体＆GT; 
＆LT; / HTML＆GT; 
 代码>  PRE> 
 
    ajax.php  EM> 强>  p> 
 \  n 
  if（isset（$ _ POST ['action']））{
 switch（$ _POST ['action']）{
  case'create'：
 create（）; 
 break; 
 case'troy'：
 destroy（）; 
 break; 
} 
} 
 
函数create（）{
 echo“创建函数 。;; 
退出; 
} 
 
函数destroy（）{
 echo“销毁函数。”; 
退出; 
} 
  code>  pre> 
  div>

答

Your case is wrong: the value in your input is Create, while in your code you check for create.

Change

switch ($_POST['action']) {
        case 'create':
            create();
            break;
        case 'destroy':
            destroy();
            break;
    }

switch ($_POST['action']) {
        case 'Create':
            create();
            break;
        case 'Destroy':
            destroy();
            break;
    }

Ajax PHP表单按钮[重复]

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