VB6.0 生成XML时，怎么设置版本号，字符集

VB6.0 生成XML时，如何设置版本号，字符集？
各位：
对VB6编程不是很熟，在网上找过很多地方，都没找到如何像.NET那样设置版本号与字符集的方法。 xmlDoc.CreateXmlDeclaration("1.0", "UTF-8", String.Empty)
请大家帮个忙，最好给一整段代码的例子。
多谢。

------解决方案--------------------

VB code


Set xXMLpi = Doc.createProcessingInstruction("xml", "version='1.0' encoding='utf-8'")

------解决方案--------------------

下面函数是我Socket传输序列化查询结果集用的、

VB code


Public Function CreateXMLString(ByVal strSql As String, ByRef lngLenght As Long) As String
    Dim strPath As String
    Dim lngRecordLine As Long
    Dim xmlDoc As DOMDocument
    Dim xmlRoot As IXMLDOMElement
    Dim xmlEle As IXMLDOMElement
    Dim xmlNode As IXMLDOMNode
    Dim xmlChildNode As IXMLDOMNode
    Dim nFieldCount As Long
    Dim rs As ADODB.Recordset
    Dim i As Integer
    
    Dim strRecord As String
    
    lngRecordLine = 0

    
    On Error GoTo ms
    Set xmlDoc = New DOMDocument
    Set xmlNode = xmlDoc.createProcessingInstruction("xml", "version='1.0' encoding='gb2312'")
    Set xmlNode = xmlDoc.insertBefore(xmlNode, xmlNode.childNodes.Item(0))
    
    Set xmlRoot = xmlDoc.createElement("RecordData")
    Set xmlDoc.documentElement = xmlRoot
     
    lngRecordLine = 1
    Set rs = New ADODB.Recordset
    
    Set rs = ExecuteSQL(strSql)
    nFieldCount = rs.Fields.Count
    Do Until rs.EOF
        Set xmlEle = xmlDoc.createElement("Record" & lngRecordLine)
        xmlRoot.appendChild xmlEle
        strRecord = ""
        For i = 1 To nFieldCount
            xmlEle.setAttribute rs.Fields(i - 1).Name, rs.Fields(i - 1).value
        Next i
        lngRecordLine = lngRecordLine + 1
        rs.MoveNext
    Loop
    rs.Close
    
    CreateXMLString = xmlDoc.xml
    lngLenght = Len(CreateXMLString)
    
    Set xmlChildNode = Nothing
    Set xmlNode = Nothing
    Set xmlEle = Nothing
    Set xmlRoot = Nothing
    Set xmlDoc = Nothing
    
    Exit Function
ms:
    
End Function

VB6.0 生成XML时，怎么设置版本号，字符集

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