有人可以为我检查代码吗?我不了解php部分.我正在尝试一种跳过验证或在其中找到代码的方法.

我尝试过的事情:

<?php
require_once(''config.php'');
session_start();

if(isset($ _ GET [''code''])){
$ content = file_get_contents(__ FILE__);
echo Highlight_string($ content);
exit();
}

if(isset($ _ POST [''solution''])&& $ _SESSION [''captcha_solution''] == $ _POST [''solution'']){
$ correct = true;
} else {
$ correct = false;
}

如果(！$正确){
$ _SESSION [''captcha_solution''] = openssl_random_pseudo_bytes(100);
}
?>


< meta charset ="utf-8">



身体{
padding-top:40像素；
padding-bottom:40px;
}




<?php if(！$ correct){?>

Can someone check the code for me? I don''t understand the php part. I''m trying a way to skip the verification or to find the code inside.

What I have tried:

<?php
require_once(''config.php'');
session_start();

if (isset($_GET[''code''])) {
$content = file_get_contents(__FILE__);
echo highlight_string($content);
exit();
}

if (isset($_POST[''solution'']) && $_SESSION[''captcha_solution''] == $_POST[''solution'']) {
$correct = true;
} else {
$correct = false;
}

if (!$correct) {
$_SESSION[''captcha_solution''] = openssl_random_pseudo_bytes(100);
}
?>


<meta charset="utf-8">



body {
padding-top: 40px;
padding-bottom: 40px;
}




<?php if (!$correct) { ?>

解决方案:

Solution :

<?php}?>

<?php } ?>

<！-/容器->
<?php}其他{?>

<!-- /container -->
<?php } else { ?>

<?php}?>

<?php } ?>