如何生成脚本的n个线程，每个线程都有自己的进程ID？

问题描述：

I'd like to start n threads of a script, each with their own process id.

I currently do this via cronjob like so:

* * * * *    php /path/to/script.php >> /log/script.log 2>&1
* * * * *    php /path/to/script.php >> /log/script.log 2>&1
* * * * *    php /path/to/script.php >> /log/script.log 2>&1

Each of these three threads all log to the same script.log, which pairs output with its pid.

How can I do the same without copy/paste from a script?

Would the following spawn each of these with a different pid (accessible from php's getmypid())? Or would they all share the same script-launcher.sh pid?

#!/bin/bash
# Let's call this `script-launcher.sh`
# Launch 3 threads at once with `script-launcher.sh 3`

N=${1-0}
for i in {1..$N}
do
   php /path/to/script.php >> /log/script.log 2>&1
done

我想启动脚本的 n em>个线程，每个线程都有自己的进程 id。 p>

我目前通过cronjob code>这样做： p>

  * * * * * php /  path / to / script.php＆gt;＆gt;  /log/script.log 2＆gt;＆amp; 1 
 * * * * * php /path/to/script.php＆gt;＆gt;  /log/script.log 2＆gt;＆amp; 1 
 * * * * * php /path/to/script.php＆gt;＆gt;  /log/script.log 2＆gt;＆amp; 1 
  code>  pre> 
 
 这三个线程中的每一个都记录到相同的 script.log  code>，其中 使用 pid  code>对输出进行输出。 p> 
 
 
如果没有从脚本中复制/粘贴，我怎么能这样做呢？ p> 
 
 

会不会 以下使用不同的 pid  code>（可从 php  code>的 getmypid（） code>访问）生成每个这些？ 或者他们都会共享相同的 script-launcher.sh  code> pid？ p> 
 
 
 ＃！/ bin / bash 
＃让我们称之为`脚本 -  launcher.sh` 
＃在{1 .. $ N} 
do 
 php / path中使用`script-launcher.sh 3` 
 
N = $ {1-0} 
 for i一次启动3个线程 /to/script.php＆gt;＆gt;  /log/script.log 2＆gt;＆amp; 1 
done 
  code>  pre> 
  div>

答

Whenever you span a new process, the new process will gain a new pid. So in this case, each time your shell script spans an instance of php, each of those copies of php will have their own pid.

The {1..$N} syntax will not work, though, so you will need to change your script to

N=${1-0}
for i in $(seq 1 $N)
do
   php /path/to/script.php >> script.log 2>&1
done

Then, if you call your script as script-launcher.sh 42, you'll get 42 instances of PHP running.

To have your php script run in the background (asynchronously), instruct bash to so with &:

   php /path/to/script.php >> script.log 2>&1 &

如何生成脚本的n个线程，每个线程都有自己的进程ID？

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