HDU 6077 17多校4 Time To Get Up 水题
Problem Description
Little Q's clock is alarming! It's time to get up now! However, after reading the time on the clock, Little Q lies down and starts sleeping again. Well, he has
Your job is to help Little Q read the time shown on his clock.
Your job is to help Little Q read the time shown on his clock.
Input
The first line of the input contains an integer 21 ASCII image of the clock screen.
All digit segments are represented by two characters, and each colon segment is represented by one character. The character ''X'' indicates a segment that is on while ''.'' indicates anything else. See the sample input for details.
All digit segments are represented by two characters, and each colon segment is represented by one character. The character ''X'' indicates a segment that is on while ''.'' indicates anything else. See the sample input for details.
Output
For each test case, print a single line containing a string ), denoting the time shown on the clock.
Sample Input
1
.XX...XX.....XX...XX.
X..X....X......X.X..X
X..X....X.X....X.X..X
......XX.....XX...XX.
X..X.X....X....X.X..X
X..X.X.........X.X..X
.XX...XX.....XX...XX.
Sample Output
02:38
题意:把字符串翻译成时间。
题解:直接利用他们的区别判断即可。
1 #include <iostream> 2 #include<cstdio> 3 #include<algorithm> 4 #include<queue> 5 #include<map> 6 #include<vector> 7 #include<cmath> 8 #include<cstring> 9 using namespace std; 10 11 char time[7+1][21+1]; 12 int check(int i) 13 { 14 int j; 15 if(time[6][i]=='X') 16 { 17 if(time[4][i+1]=='.') 18 return 0; 19 else if(time[2][i]=='.') 20 return 2; 21 else if(time[2][i+3]=='.') 22 return 6; 23 else 24 return 8; 25 } 26 else 27 { 28 if(time[2][i]=='X') 29 { 30 if(time[1][i+1]=='X') 31 { 32 if(time[2][i+3]=='X') 33 return 9; 34 else 35 return 5; 36 } 37 else 38 return 4; 39 } 40 else 41 { 42 if(time[4][i+1]=='.') 43 { 44 if(time[1][i+1]=='X') 45 return 7; 46 else 47 return 1; 48 } 49 else 50 return 3; 51 } 52 } 53 } 54 55 int main() 56 { 57 int a,b,c,d; 58 int T; 59 scanf("%d",&T); 60 while(T--) 61 { 62 for(int i=1;i<=7;i++) 63 for(int j=1;j<=21;j++) 64 cin>>time[i][j]; 65 a=check(1); 66 b=check(6); 67 c=check(13); 68 d=check(18); 69 printf("%d%d:%d%d ",a,b,c,d); 70 } 71 return 0; 72 }