python 由递归的dict构建树的画图代码
createPlot(mytree)方法实现。
其中myTree是一个字典，调用retrieveTree(0)可以获得一个字典的样式。
Last login: Thu Feb 23 19:07:53 on ttys000 B000000060143:~ zhanghao44$ ls 4 Desktop IdeaProjects Music PycharmProjects 4a Documents Library Pictures CLionProjects Downloads Movies Public B000000060143:~ zhanghao44$ cd Desktop/ B000000060143:Desktop zhanghao44$ ls help machinelearninginaction ps-dsp 终端 备份 屏幕快照 2017-02-22 下午7.36.56.png 屏幕快照 2017-02-22 下午7.41.27.png 屏幕快照 2017-02-22 下午7.45.55.png 张浩出勤统计.xlsx B000000060143:Desktop zhanghao44$ cd machinelearninginaction/ B000000060143:machinelearninginaction zhanghao44$ ls Ch02 Ch05 Ch08 Ch11 Ch14 Ch03 Ch06 Ch09 Ch12 Ch15 Ch04 Ch07 Ch10 Ch13 README.rst B000000060143:machinelearninginaction zhanghao44$ cd Ch03 B000000060143:Ch03 zhanghao44$ ls classifierStorage.txt treePlotter.py trees.py lenses.txt treePlotter.pyc trees.pyc B000000060143:Ch03 zhanghao44$ vi trees.py B000000060143:Ch03 zhanghao44$ vi treePlotter.py B000000060143:Ch03 zhanghao44$ vi treePlotter.py plotTree.totalD = float(getTreeDepth(inTree)) plotTree.xOff = -0.5/plotTree.totalW; plotTree.yOff = 1.0; plotTree(inTree, (0.5,1.0), '') plt.show() def createPlot1(): fig = plt.figure(1, facecolor='white') fig.clf() createPlot.ax1 = plt.subplot(111, frameon=False) #ticks for demo puropses plotNode('a decision node', (0.5, 0.1), (0.1, 0.5), decisionNode) plotNode('a leaf node', (0.8, 0.1), (0.3, 0.8), leafNode) plt.show() def retrieveTree(i): listOfTrees =[{'no surfacing': {0: 'no', 1: {'flippers': {0: 'no', 1: 'yes'}}}}, {'no surfacing': {0: 'no', 1: {'flippers': {0: {'head': {0: 'no', 1: 'yes'}}, 1: 'no'}}}} ] return listOfTrees[i] #createPlot(thisTree)