如何将变量从一个页面传递到另一个页面？

问题描述：

I am creating a website, that has many pages. You can change the number of posts shown in each page through a drop down menu. My problem starts if i change the amount of posts move to the next page it comes back to default.

e.x default posts shown is 30, and then i change it to 40. The moment i change page it comes down to 30 again on the next page.

I have tried something like that but unfortunately doesn't work.

<form method="get" name="SkipPage">
<select name="results_no" onChange="document.forms['SkipPage'].submit()"> `
<?php
....
?>
</select>
</form>

$reults_no = isset($_GET['results_no']) ? $_GET['results_no'] : 30;

我正在创建一个有很多页面的网站。您可以通过下拉菜单更改每个页面中显示的帖子数量。我的问题开始，如果我改变帖子的数量移动到下一页它恢复默认。 p>

ex默认帖子显示为30，然后我将其更改为40.当下我更改页面在下一页再次降至30。 p>

我尝试了类似的东西，但遗憾的是无效。 p>

 ＆lt; form method =“get”name =“SkipPage”＆gt; 
＆lt; select name =“results_no”onChange =“document.forms ['SkipPage']。submit（）”＆gt;  `
＆LT;？PHP 
 .... 
＆GT; 
＆LT; /选择＆GT; 
＆LT; /形式＆GT; 
 代码>  PRE> 
 
   $  reults_no = isset（$ _ GET ['results_no']）？  $ _GET ['results_no']：30;  code>  p> 
  div>

答

try to use hidden intput

<input type="hidden" name="myHiddenVar" value="<?php echo $myVar ?>"

Then you can use your var with $_POST["myHiddenVar"];

But if you want a persistent choice use sessions. session_start(); on each page and access/edit your var with $_SESSION['myVar'];

答

If you want to make a user choice persistent, the usual solution is to save it in a cookie.

EDIT: or in SESSION but my point is that you don't have to pass the value as a GET parameter for each link followed by the user. You set it once and test if set on each page that need it.

如何将变量从一个页面传递到另一个页面？

相关推荐