day06作业

1. 给定年龄，用户可以猜三次年龄，年龄猜对，让用户选择两次奖励，用户选择两次奖励后退出

   age=18
   j=2
   count=0
   prize_dict={0:'布娃娃',1:'变形金刚',2:'奥特曼',3:'Python'}
   while count<3:
       inp_age=input('Please input your age:')
       if not inp_age.isdigit():
           print('Please input digit')
           continue
       inp_age_int=int(inp_age)
       if inp_age_int==age:
           print('Congratulations,you got it right .')
           print(prize_dict)
           for i in range(2):
               prize_choice=input('Please input the number which goods you want:')
               if prize_choice!='n':
                   print(f'Congratulations ,you acquire:',{prize_dict[int(prize_choice)]})
               else:
                   break
           break
       elif inp_age_int<age:
           print('太小了')
       elif inp_age_int>age:
           print('太大了')
       j=2-count
       print('你还有%s次机会'%j)
       count=count+1
   

2. 作业需求：

   1. 运行程序输出第一级菜单

   2. 选择一级菜单某项，输出二级菜单，同理输出三级菜单

   3. 菜单数据保存在文件中

   4. 让用户选择是否要退出

   5. 有返回上一级菜单的功能

date = {
    '北京':{
        '昌平':{
            '沙河':['腾讯','华为','小米'],
            '天通苑':['百度','链家地产','我爱我家地产']
        },
        '朝阳':{
            '望京':['奔驰','宝马','福特','长安'],
            '国贸':['CICC','ATCC','HP'],
            '东直门':['华硕','阿里巴巴','京东']
        }
    },
    '云南':{
        '昆明':{
            '城南':['大学城','双都飞'],
            '城北':['工业区','农业区']
        },
        '西双版纳':{
            '南城':['旅游区','度假区','休闲区'],
            '西城':['娱乐区','双阳区']
        },
    },
    '河南':{
        '郑州':{
            '二七区':['郑州火车站','二七纪念塔'],
            '郑东新区':['大学城','绿博园']
        },
        '南阳':{
            '宛城区':['南阳理工','医圣祠'],
            '卧龙区':['南阳师院','武侯祠']
        }
    }
}
exit_1 = 1
while exit_1 :
    for i in date :
        print(i)
    choice = input('选择一个进入:')
    if choice in date :
        while exit_1:
            for two in date[choice]:
                print('	',two)
            choice2 = input('请选择一个进入,返回上一层请输入back')
            if choice2 in date[choice]:
                while exit_1:
                    for three in date[choice][choice2]:
                        print('	',three)
                    choice3 = input('请选择一个输入,返回上一层请输入back')
                    if choice3 in date[choice][choice2]:
                        while exit_1:
                            for four in date[choice][choice2][choice3]:
                                print('	',four)
                            choice4 = input('返回上一层请输入back,退出请输入exit')
                            if choice4 == 'back':
                                break
                            elif choice4 == 'exit':
                                exit_1 = 0
                    elif choice3 == 'back':
                              break
            elif choice2 == 'back':
                break