win32中怎么“打开文件”？高手来吧，解决后立马给分

win32中如何“打开文件”？？？？高手来吧，解决后立马给分
win32中如何“打开文件”？就像我们平时用的保存打开一样！！可以在任意路径下打开任意的文件！！谁能给我源代码！我立马给分！

------解决方案--------------------
打开文件对话框
OPENFILENAME ofn; // common dialog box structure
char szFile[260]; // buffer for file name
HWND hwnd; // owner window
HANDLE hf; // file handle

// Initialize OPENFILENAME
ZeroMemory(&ofn, sizeof(ofn));
ofn.lStructSize = sizeof(ofn);
ofn.hwndOwner = hwnd;
ofn.lpstrFile = szFile;
//
// Set lpstrFile[0] to '\0 ' so that GetOpenFileName does not
// use the contents of szFile to initialize itself.
//
ofn.lpstrFile[0] = '\0 ';
ofn.nMaxFile = sizeof(szFile);
ofn.lpstrFilter = "All\0*.*\0Text\0*.TXT\0 ";
ofn.nFilterIndex = 1;
ofn.lpstrFileTitle = NULL;
ofn.nMaxFileTitle = 0;
ofn.lpstrInitialDir = NULL;
ofn.Flags = OFN_PATHMUSTEXIST | OFN_FILEMUSTEXIST;

// Display the Open dialog box.

if (GetOpenFileName(&ofn)==TRUE)
hf = CreateFile(ofn.lpstrFile, GENERIC_READ,
0, (LPSECURITY_ATTRIBUTES) NULL,
OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL,
(HANDLE) NULL);