使用Golang中的ParseFloat将字符串输入转换为float64
I've just started learning Go and I'm trying to convert a string from standard input to a float64 so I can perform an arithmetic operation on the input value.
The output returns "0 feet converted to meters gives you 0 meters" regardless of the input value. I can't figure out why the value is zero after invoking ParseFloat on the input.
If someone could please point out to me why this is happening, I would greatly appreciate it.
const conversion float64 = 0.3048
func feetToMeters (feet float64) (meters float64) {
return feet * conversion
}
func main(){
fmt.Println("
This program will convert feet to meters for you!
")
reader := bufio.NewReader(os.Stdin)
fmt.Println("Enter feet value:
")
feet, _ := reader.ReadString('
')
feetFloat, _ := strconv.ParseFloat(feet, 64)
meters := feetToMeters(feetFloat)
fmt.Printf("%v feet converted to meters give you %v meters",feetFloat,meters)
}
我刚刚开始学习Go,我正尝试将字符串从标准输入转换为float64,所以我 可以对输入值进行算术运算。 p>
无论输入值如何,输出都会返回“ 0英尺转换为米,您得到0米”。 在输入上调用ParseFloat之后,我无法弄清楚为什么该值为零。 p>
如果有人可以指出为什么会这样,我将不胜感激。 p>
const转换float64 = 0.3048 \ n
func feetToMeters(英尺float64)(米float64){
返回英尺*转换
}
func main(){
fmt.Println(“
此程序将为您将英尺转换为米!
“)
读者:= bufio.NewReader(os.Stdin)
fmt.Println(”输入英尺值:
“)
英尺,_:= reader.ReadString('
')
feetFloat,_:= strconv.ParseFloat(feet,64)
米:= feetToMeters(feetFloat)
fmt.Printf(“%v英尺转换为米会为您提供%v米”, feetFloat,meters)
}
code> pre>
div>
The problem is that you try to parse "x.x
"
, e.g: 1.8
. And this returns an error: strconv.ParseFloat: parsing "1.8
": invalid syntax
. You can do a strings.TrimSpace
function or to convert feet[:len(feet)-1]
to delete
character
With strings.TrimSpace()
(you need to import strings
package):
feetFloat, _ := strconv.ParseFloat(strings.TrimSpace(feet), 64)
Wtih feet[:len(feet)-1]
:
feetFloat, _ := strconv.ParseFloat(feet[:len(feet)-1], 64)
Output in both cases:
10.8 feet converted to meters give you 3.2918400000000005 meters