啊请问jsp有关问题

高手救命啊请教jsp问题。
HTTP Status 500 - java.lang.NullPointerException

--------------------------------------------------------------------------------

type Exception report

message java.lang.NullPointerException

description The server encountered an internal error that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: java.lang.NullPointerException
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)

root cause

java.lang.NullPointerException
org.apache.jsp.index_jsp._jspService(index_jsp.java:149)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)

note The full stack trace of the root cause is available in the Apache Tomcat/7.0.47 logs.

以上为打开的报错内容

在服务器上可以使用，我把SQL库完全备份到这台机器，源码也发在这台机器上，一样的环境，为啥不行呢？
另外问一下，SQL链接的用户和密码，哪张表在TOMCAT的哪里？

------解决方案--------------------



<%@ page contentType="text/html; charset=gb2312"  errorPage="" %>

<%@ page import="java.sql.*"%> 

<%@ page import="java.util.*"%>

<%@ page import="java.io.*"%>

<%@ page import="java.util.Date"%>

<%@ page import="java.text.*"%>

<jsp:useBean id="Databbb" scope="page" class="com.db.CGlobalFunction"  />

<%Databbb.getConn(config);%>

<%

    ResultSet rs;

String mysql,sYear="",aaid="",sName="";

        String txtsrid="",txtname="";

txtsrid = (String)request.getParameter("txtsrid");

txtname	 = Databbb.toChinese(request.getParameter("txtname"));

String txtsrid1 = (String)request.getParameter("txtsrid1");

String txtname1	 = (String)request.getParameter("txtname1");	

if (txtsrid==null){ if(txtsrid1==null) {aaid = "";} else {aaid=txtsrid1;}} else {aaid = txtsrid;}

if (txtname==null){  if(txtname1==null) {aaname= "";} else {sName=txtname1;}} else {aaname= txtname;}	

%>

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312">

<title></title>

<link href="css/xmwuye.css" rel="stylesheet" type="text/css">

<link href="../css/xmwuye.css" rel="stylesheet" type="text/css">

</head>

<body>

<form name="studform" method="post" action="" autocomplete="off">

  <table width="70%" border="0" align="center" cellpadding="0" cellspacing="0">

    <tr  bgcolor="#F2F8FF">

      <td width="12%"><strong>号码:</strong></td>

      <td width="35%"><input name="txtsrid" type="text" id="txtsrid"  value="<%=aaid%>" size="19"></td>

      <td width="12%"><strong>新号码:</strong></td>

      <td width="28%"><input name="txtname" type="text" id="txtname"  value="<%=sName%>" size="19"></td>

      <td width="13%"><input type="submit" name="Submit" value="提交"></td>

    </tr>

  </table>

  <p>&nbsp;  </p>

  <p>

    <%

        mysql = " select b.idname,b.srid,b.stdname,case b.sex when '1' then '男' when '2' then '女' end ";

啊请问jsp有关问题

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