一个关于C++错误的疑惑!
一个关于C++异常的疑惑!!!~~~
下面代码:
想问 是不是在C++中不将异常throw 就不会抓住呢?
因为在这个程序中是抓不住的!~
------解决方案--------------------
谁说C++中1/0时会抛异常?
下面代码:
- C/C++ code
#include "stdafx.h" #include "iostream" #include "exception" using std::exception; using std::cin; using std::cout; using std::endl; int hmean(int a,int b); int _tmain(int argc, _TCHAR* argv[]) { int x,y,z; cout<<"Enter two numbers :"; while(cin>>x>>y&& x!=0&&y!=0) { try { z = hmean(x,y); } catch(exception e) { cout<<e.what()<<endl; cout<<"Enter a new pair of numbes: "; continue; } std::cout<<"Harmonic nean of "<<x<<" and "<<y <<" is "<<z<<endl; cout<<"Entre next set of numbers <0 0to quit>: "; } return 0; } int hmean(int a,int b) throw (exception ) { cout<<" 抓不住!~~~~"<<endl; return 2*a*b/(a+b); //分母为零时会抛异常 }
想问 是不是在C++中不将异常throw 就不会抓住呢?
因为在这个程序中是抓不住的!~
------解决方案--------------------
谁说C++中1/0时会抛异常?