11

def get_min(li):
    low = 0
    high = len(li) - 1
    mid = low
    while li[low] >= li[high]:  # 一般low的元素>=high的元素
        if high - low == 1:
            mid = high
            break
        if (li[low] == li[high] and li[mid] == li[low]):  # 特殊情况:无法判断 mid位于左子数组还是右子数组
            return get_min_order(li)
        mid = (low + high) // 2
        if li[mid] >= li[low]:  # 如果mid大于low位置的元素,则最小值应该在mid 的后面
            low = mid
        elif li[mid] <= li[high]:  # 如果mid小于于high位置的元素,则最小值应该在mid 的前面
            high = mid
    return li[mid]


def get_min_order(li):
    # 顺序查找
    min = li[0]
    for i in li:
        if i < min:
            min = i
    return min


li = [4, 5, 6,1, 2, 3]
print(get_min(li))