SGU 117 Counting

117. Counting

time limit per test: 0.5 sec.
memory limit per test: 4096 KB

Find amount of numbers for given sequence of integer numbers such that after raising them to the M-th power they will be divided by K.

Input

Input consists of two lines. There are three integer numbers N, M, K (0<N, M, K<10001) on the first line. There are N positive integer numbers ? given sequence (each number is not more than 10001) ? on the second line.

Output

Write answer for given task.

Sample Input

4 2 50
9 10 11 12

Sample Output

Author	: Michael R. Mirzayanov
Resource	: PhTL #1 Training Contests
Date	: Fall 2001

SGU中难得的水题。。。。怒A。。。

#include <iostream>
#include <cstring>
#include <cstdio>
#include <cmath>

using namespace std;

int prim[11000];
int sigK[11000],sigA[11000];

int main()
{
    int n,m,k;
    cin>>n>>m>>k;
    memset(prim,-1,sizeof(prim));
    prim[1]=prim[0]=0;
    for(int i=2;i<=sqrt(11000);i++)
    {
        if(prim==0) continue;
        for(int j=2*i;j<11000;j+=i)
        {
            prim[j]=0;
        }
    }
    for(int i=0;i<11000;i++)
    {
        if(prim!=0)
        {
            while(k%i==0)
            {
                k/=i;
                sigK++;
            }
        }
    }
    int ans=0;
    for(int i=0;i<n;i++)
    {
        int a;
        cin>>a;
        memset(sigA,0,sizeof(sigA));
        for(int j=0;j<11000;j++)
        {
            if(prim[j]!=0)
            {
                while(a%j==0)
                {
                    a/=j;
                    sigA[j]++;
                }
                sigA[j]*=m;
            }
        }
        bool OK=true;
        for(int j=0;j<11000;j++)
        {
            if(sigK[j])
            {
                if(sigA[j]<sigK[j])
                {
                   OK=false;
                   break;
                }
            }
        }
        if(OK) ans++;
    }
    cout<<ans<<endl;
    return 0;
}

* This source code was highlighted by YcdoiT. ( style: Codeblocks )

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