LeetCode OJ 题目: 解题思路: 代码:

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

解题思路:

递归求得左子树的深度left_depth,右子树的深度right_depth,则 ans = max(left_depth, right_depth) + 1;

代码:

 1 /**
 2  * Definition for binary tree
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     int maxDepth(TreeNode *root) {
13         if (root == NULL){
14             return 0;
15         }
16         int left_depth = maxDepth(root->left);
17         int right_depth = maxDepth(root->right);
18         return max(left_depth, right_depth) + 1;
19         
20     }
21     inline int max(int a, int b) {
22         return a > b ? a : b;
23     }
24 };