C语言程序，数组元素无法赋值，请大家帮忙看看解决方案

C语言程序，数组元素无法赋值，请大家帮忙看看
请大家帮忙看看我的程序，明明写了赋值语句怎么会不赋值呢？
我设断点看过了，spiral[count]没有被赋成matrix[i][j]的值，每次都不变
十分不解...
我的程序：
#include<iostream.h>
#include<string.h>

#define MAXS 20
#define MAX 400

typedef char MS[MAXS][MAXS];
typedef char String[MAX];

int H;
void CreateMatrix(int width, String ptext, MS &matrix)
{//Create a Matrix with the width of key length
int l,i,j,ct,height;
//find out the height first
  l=strlen(ptext);
  if ((l%width)==0) height=l/width;
  else height=l/width +1;
  H=height;//H will be used in the procedure Tex3
  ct=0;
  for (i=0;i<height;i++ )
  {
  for (j=0;j<width;j++) 
  {
  matrix[i][j]=ptext[ct];
  ct=ct+1;
  }
  }
}
void SpiralString(int height,int width, MS matrix, String &spiral)
{//read the matrix spirally and return the spiral string
int i,j,count,flag,east,north,west,south;
flag=1; count=0;
east=width;
north=height;
i=0; j=0;
west=0;
south=0;
while(true)
{
  if( flag==1 )//flag=1 means go Eastward and Northward
  {
  for (;j<east;j++)
  {
  spiral[count]=matrix[i][j];//create spiral string
  count++;
  }
   
  j--;
  i++; //move to the next line
  east--;

  for( ;i<north ;i++) 
  {
  spiral[count]=matrix[i][j];//create spiral string 
  count++;
  }  
  i--;
  j--;
  north--;

  flag=-1;
  }
  else //flag=-1 means go Westward and Southward
  {
  for(;j>=west;j-- )  
  {
  spiral[count]=matrix[i][j];//create spiral string
  count++;
  }
   
  j++;
  i--;
  west++;

  for( ;i>=south+1;i--)
  {
  spiral[count]=matrix[i][j];//create spiral string
  count++;
  }
  j++;
  i++;
  south++;
  flag=1;
  }
  if (count>height*width) break; //browsed all the elements
}  
}

void PrintStr(String str)
{//print the string
 for(int i=0; i < int(strlen(str)) ;i++)
  cout<<str[i];
}

void main()
{
String str,Ptext;
MS matrix;
cout<<"Input the text:"<<endl;
cin>>Ptext;//get text
CreateMatrix(3,Ptext,matrix); //biuld matrix
cout<<endl;
SpiralString(4,3,matrix,str);
cout<<"The spiral string is:"<<SS<<endl;
PrintStr(str);
} 


------解决方案--------------------
lz定义了数组有空间的，试了一下好像跳不出循环可以，改了
...
if(count>=height*width）break；
}
spiral[count]='\0' //c字串记得结尾补0
}

输入12个字符后输出如lz所要是螺旋的...