asp.net mvc前端post提交json数据给controller,后台参数怎么对应接收

asp.net mvc前端post提交json数据给controller,后台参数如何对应接收?
前端程序

<div class="right_body">
    <div class="body">
        <div class="top_subnav">CMS内容管理平台 > 首页 > 发布文章</div>
        <div class="title_h3">
            发布文章
        </div>
        <p class="line" style="margin-top:0;">
        </p>
        <div class="news">
            <div>
                @using (Html.BeginForm(null, null, FormMethod.Post, new { id = "newsinsertform" }))
                {
                    <p><span>文章标题:</span>@Html.TextBoxFor(a => a.News_Title, new { @class = "newstitle" })</p>
                    <p><span>文章类别:</span>@Html.DropDownListFor(a => a.NewsTypes.Id, (SelectList)ViewData["NewsType"], new { @class = "newstype" })</p>
                    <p><span>图片新闻:</span>@Html.CheckBoxFor(a => a.IsPic, new { @class = "IsPic" })<input type="file" id="fileupload" name="fileupload" class="upload" /></p>
                    <p><span>文章内容:</span></p>
                    <hr />
                    <div class="htmleditor">@Html.TextAreaFor(a => a.News_Content, new { @class = "newscontent" })</div>
                }
            </div>
        </div>
        <p class="line" style="margin-top:0;">
        </p>
        <div class="f">
            <img src="~/Content/themes/manage/images/submit.gif" id="sub" />
        </div>
        <div id="element_to_pop_up">
            <div class="message">恭喜你,提交成功了!</div>
        </div>
    </div>
</div>

js代码如下:

 $("#sub").click(function () {
            if ($(".newstitle").val() != "" && $(".newstitle").val() != "标题不能为空") {
                $("#newsinsertform").ajaxSubmit({
                    type: "post",
                    dataType: "json",
                    url: "/Manage/NewsInsert",
                    data: JSON.stringify({ News_Title: $(".newstitle").val().trim(), News_Content: editor.document.getBody().getHtml(), News_Writer: "admin", IsPic: $(".IsPic").val().trim(), News_TypeId: $(".newstype").val() }),
                    success: function () {//提示提交成功
                        $("#element_to_pop_up").bPopup({
                            autoClose: true,
                            speed: 1500
                        });
                    },
                    error: function (xmlHttpRqquest, textStatus, errorThrown) {
                        alert(errorThrown);
                    }
                });
                
            } else {
                $(".newstitle").Text("<span style='color:red'>*标题不能为空<span>");
            }
        });


后台对应的controller

        /// <summary>
        /// 发布页面()
        /// </summary>
        /// <returns></returns>
        public ActionResult NewsInsert()
        {
            var b = new NewsTypes();
            var newstypelist = b.GetList();
            var selectlist = new SelectList(newstypelist, "Id", "TypeName");
            ViewData["NewsType"] = selectlist;
            return View();
        }

        /// <summary>
        /// 发布页面
        /// </summary>
        /// <param name="str"></param>
        /// <returns></returns>
        [HttpPost]
        public ActionResult NewsInsert(M.News str)
        {
            if (!ModelState.IsValid)
            {
                return View("NewsInsert", str);
            }
            HttpFileCollection hfc = System.Web.HttpContext.Current.Request.Files;
            if (hfc.Count > 0)
            {
                String imgPath = "";
                string filename = Guid.NewGuid() + "." + hfc[0].FileName.Substring(hfc[0].FileName.LastIndexOf(".", StringComparison.Ordinal) + 1);
                imgPath = "/images/" + filename;
                String physicalPath = Server.MapPath(imgPath);
                hfc[0].SaveAs(physicalPath);
                str.News_Picture = filename;
            }
            _bn.Insert(str);
            return Json(str, JsonRequestBehavior.AllowGet);
        }


现在的问题是后台M.News str这个参数获取到的参数不全,请大家指点一下!谢谢!!!
------解决思路----------------------
model.news=request[ " 前台要穿过来的参数 "] 这样就传给model了 
------解决思路----------------------
用Request.Form["News_Title"]试一试
------解决思路----------------------
1:不用加JSON.stringify
2:js有.trim()的用法吗...我记得应该是$.trim()....

3:你的data:{}里没有把图片传过来....