SQL运用inner join提示报错
SQL使用inner join提示报错
错误代码:
消息 156,级别 15,状态 1,第 27 行
关键字 'on' 附近有语法错误。
------解决方案--------------------
SELECT 医疗机构名称=shospitalname,
人次=count(*),
总费用= sum(sbczfy),
自费药=sum(sbfh_medi),
自费项目=sum(sbfh_medi+sbfh_treat+sbfh_qt),
补偿总额= sum(sbc_bcje) ,
平均住院天数=avg(szydays),
平均床日费用=(sum(sbczfy)/count(*))/avg(szydays),
均次费用=sum(sbczfy)/count(*)
FROM NH_InchgBC_List a
inner join(
SELECT 医疗机构名称=shospitalname,
人次=count(*),
总费用= sum(sbczfy),
自费药=sum(sbfh_medi),
自费项目=sum(sbfh_medi+sbfh_treat+sbfh_qt),
补偿总额= sum(sbc_bcje) ,
平均住院天数=avg(szydays),
平均床日费用=(sum(sbczfy)/count(*))/avg(szydays),
均次费用=sum(sbczfy)/count(*)
FROM NH_InchgBC_List b
where syear = 2011
and shospitaltype = '定点地市医疗机构'
and dchgdate > '2011-01-01' and dchgdate < '2011-11-25'
GROUP BY shospitalname)
on a.shospitalname = b.shospitalname
where syear = 2012
and shospitaltype = '定点地市医疗机构'
and dchgdate > '2012-01-01' and dchgdate < '2012-11-25'
GROUP BY shospitalname
错误代码:
消息 156,级别 15,状态 1,第 27 行
关键字 'on' 附近有语法错误。
------解决方案--------------------
SELECT 医疗机构名称=shospitalname,
人次=count(*),
总费用= sum(sbczfy),
自费药=sum(sbfh_medi),
自费项目=sum(sbfh_medi+sbfh_treat+sbfh_qt),
补偿总额= sum(sbc_bcje) ,
平均住院天数=avg(szydays),
平均床日费用=(sum(sbczfy)/count(*))/avg(szydays),
均次费用=sum(sbczfy)/count(*)
FROM NH_InchgBC_List a
inner join(
SELECT 医疗机构名称=shospitalname,
人次=count(*),
总费用= sum(sbczfy),
自费药=sum(sbfh_medi),
自费项目=sum(sbfh_medi+sbfh_treat+sbfh_qt),
补偿总额= sum(sbc_bcje) ,
平均住院天数=avg(szydays),
平均床日费用=(sum(sbczfy)/count(*))/avg(szydays),
均次费用=sum(sbczfy)/count(*)
FROM NH_InchgBC_List b
where syear = 2011
and shospitaltype = '定点地市医疗机构'
and dchgdate > '2011-01-01' and dchgdate < '2011-11-25'
GROUP BY shospitalname) b
on a.shospitalname = b.shospitalname