关于json解析的有关问题

关于json解析的问题
{"code":"00",
"id":{"num":"0","istarget":"false"},
"mail":{"num":"1","istarget":"true"},
"cell":{"num":"1","istarget":"false"},
"name":{"num":0},
"addr":{"num":1},
"commodity":{},
"media":{"财经":{"num":"2.0"},"历史/社会/人文":{"num":"1.0"},"科学/教育":{"num":"2.0"}},
"ec":{"3C 数码": {"num": "9","level1": "0.6183662429189318","price": "536.2"},
"运动娱乐": {"num": "284","level1": "0.9798223497689971","price": "2746.9"}}
}

请问怎么解析这个json，上面的能读出来，但是media和ec这两个不知道怎么建类

我用的DataContractJsonSerializer
------解决方案--------------------
刚好最近写了篇博客
http://blog.csdn.net/qq807081817/article/details/37919339

private void button1_Click(object sender, EventArgs e)

{

    string json = System.IO.File.ReadAllText(@"C:\Users\Administrator\Desktop\1.txt", Encoding.Default);

    string value;

    Helper.Json.GetValue(json, "media", out value);

    this.textBox1.Text = value;

}

private void button1_Click(object sender, EventArgs e)

{

    string json = System.IO.File.ReadAllText(@"C:\Users\Administrator\Desktop\1.txt", Encoding.Default);

    string value;

    Helper.Json.GetValue(json, "media", out value);

    Helper.Json.GetValue(value, "财经", out value);

    this.textBox1.Text = value;

}

------解决方案--------------------
fastCSharp

using fastCSharp;

        class X

        {

            string code;

            public nameNum[] Media;

            fastCSharp.setup.cSharp.json.node media

            {

                set { Media = value.Dictionary.getArray(node => nameNum.Get(node)); }

            }

            public nameNum[] Ec;

            fastCSharp.setup.cSharp.json.node ec

            {

                set { Ec = value.Dictionary.getArray(node => nameNum.Get(node)); }

            }

        }

        class nameNum

        {

            string name;

            string num;

            string level1;

            string price;

            internal static nameNum Get(KeyValuePair<subString, fastCSharp.setup.cSharp.json.node> node)

            {

                nameNum value = fastCSharp.setup.cSharp.json.parse.Get<nameNum>(node.Value);

                value.name = node.Key;

                return value;

            }

        }

            X value = fastCSharp.setup.cSharp.json.parse.Get<X>(json);

------解决方案--------------------

  [DataMember(Name="历史/社会/人文")]

        public string *

这个应该是你想要的