杭电OJ(HDU)-ACMSteps-Chapter Three-《FatMouse' Trade》《现年暑假不AC》《排名》《开门人和关门人》

杭电OJ(HDU)-ACMSteps-Chapter Three-《FatMouse' Trade》《今年暑假不AC》《排名》《开门人和关门人》

http://acm.hdu.edu.cn/game/entry/problem/list.php?chapterid=1§ionid=3

1.3.1 FatMouse' Trade
#include <algorithm>
/*
题意：价值/代价的比值来排序，买比值大的。
Sample Input
5 3 
7 2
4 3
5 2
20 3 25 18 24 15 15 10 -1 -1
 
Sample Output
13.333 31.500
*/
#include<stdio.h>
#include<stdlib.h>

const int MAXN = 1010;
struct node
{
    double j,f;
    double r;
}a[MAXN];
int cmp(const void *a,const void *b)
{
    struct node *c=(node *)a;
    struct node *d=(node *)b;
    if(c->r > d->r) return -1;
    else return 1;
}    
int main()
{
    int N;
    double M;
    double ans;
    while(scanf("%lf%d",&M,&N))
    {
        if(M==-1&&N==-1) break;
        for(int i=0;i<N;i++)
        {
           scanf("%lf%lf",&a[i].j,&a[i].f);
           a[i].r=(double)a[i].j/a[i].f;
        }    
        qsort(a,N,sizeof(a[0]),cmp);
        ans=0;
        for(int i=0;i<N;i++)
        {
            if(M>=a[i].f)
            {
                ans+=a[i].j;
                M-=a[i].f;
            }    
            else 
            {
                ans+=(a[i].j/a[i].f)*M;
                break;
            }    
        }   
        printf("%.3lf\n",ans); 
    }    
    return 0;
}    

1.3.2	今年暑假不AC
*
Sample Input
12
1 3
3 4
0 7
3 8
15 19
15 20
10 15
8 18
6 12
5 10
4 14
2 9
0
 
Sample Output
5
*/
#include <stdio.h>  
#include <stdlib.h>  
#include <string.h>  
  
struct ti  
{  
    int s, e;  
};  
  
int compare(const void *a, const void *b);  
  
int main()  
{  
    int i, n, k;  
    struct ti tis[101], temp[101];  
  
    while(scanf("%d", &n) != EOF)  
    {  
        if(n == 0)  
            break;  
  
        for(i = 0; i < n; i ++)  
        {  
            scanf("%d %d", &tis[i].s, &tis[i].e);  
        }  
  
        qsort(tis, n, sizeof(tis[0]), compare);  
  
        k = 0;  
        temp[k] = tis[0];  
  
        for(i = 1; i < n; i ++)  
        {  
            if(tis[i].s >= temp[k].e)  
                temp[++ k] = tis[i];  
        }  
        printf("%d\n", k + 1);  
    }  
    return 0;  
}  
  
int compare(const void *a, const void *b)  
{  
    const struct ti *p = (ti*)a;  
    const struct ti *q = (ti*)b;  
  
    return p->e - q->e;  
}  

1.3.3	排名

#include <string>
#include <stdio.h>
#include <algorithm>
using namespace std;
#define N 1000
int que[10];
struct node
{
	char name[20];
	int num;
	int score;
}stu[N];

bool cmp(const node& a, const node& b)
{
	if (a.score == b.score)
	{
		return strcmp(a.name, b.name) < 0 ? 1:0;
	}
	else
	{
		return a.score > b.score;
	}
}

/* 联系字典序：第1行给出考生人数N ( 0 < N < 1000 )、考题数M ( 0 < M < = 10 )、分数线（正整数）G；
第2行排序给出第1题至第M题的正整数分值；
以下N行，每行给出一名考生准考证号（长度不超过20的字符串）、该生解决的题目总数m、以及这m道题的题号 
4 5 25
10 10 12 13 15
CS004 3 5 1 3
CS003 5 2 4 1 3 5
CS002 2 1 2
CS001 3 2 3 5
*/
int main()
{
	int student, question, judge, x, count;
	while(scanf("%d", &student),student)
	{
		count = 0;
		for (int i = 1; i <= student;++i)
		{
			stu[i].score = 0;
			stu[i].num = 0;
		}
		scanf("%d%d",&question, &judge);
		for (int i = 1;i <= question;++i)
		{
			scanf("%d",&que[i]);
		}
		for (int i = 1;i <= student;++i)
		{
			scanf("%s%d",&stu[i].name,&stu[i].num);
			while(stu[i].num--)
			{
				scanf("%d",&x);
				stu[i].score += que[x];
			}
			if (stu[i].score >= judge)
				count ++;
		}
		sort(stu+1,stu+1+student,cmp);
		printf("%d\n",count);
		for (int i = 1;i <= student;++i)
		{
			if (stu[i].score >= judge)
				printf("%s %d\n",stu[i].name, stu[i].score);
			else
				break;
		}
	}
	return 0;
}

1.3.4 开门人和关门人
#include "stdafx.h"

#include <iostream>  
#include <string>  
using namespace std ;  
  
  
struct node  
{  
    string name, timee;  
}maxt, mint;//记录最大和最小的结构体  
  
int main()  
{  
    int t, n;  
    string s,mis, mas;  
    cin>>t;  
  
  
    while (t--)  
    {  
        cin>>n;  
        n--;  
        cin>>s>>mint.timee>>maxt.timee;  
        mint.name = maxt.name = s;  
  
        while (n--)  
        {  
            cin>>s>>mis>>mas;  
            if (mis < mint.timee)  
            {  
                mint.name = s;  
                mint.timee = mis;  
            }  
            if (mas > maxt.timee)  
            {  
                maxt.name = s;  
                maxt.timee = mas;  
            }  
        }  
  
        cout<<mint.name<<" "<<maxt.name<<endl;  
    }  
  
    return 0;  
}