为什么即使在PHP中成功建立连接后,我也无法将图像文件上传到远程FTP服务器?
I want to connect to one remote FTP server and upload image file to that server at some specific location. I'm able to connect to the server but not able to upload the file.
Every time the function ftp_put()
is returning false. I debugged the code a lot but I'm not understanding where I'm making the mistake.
Following is my code:
HTML code:
<form method="post" enctype="multipart/form-data" action="xyz.php">
<input type="file" name="student_image" id="student_image" />
</form>
PHP code(xyz.php):
$t = time();
$allowed_image_extension = array("jpg","jpeg","gif","png","JPG","JPEG","GIF","PNG");
if(!empty($_FILES['student_image']['name'])) {
$ext = pathinfo($_FILES['student_image']['name'], PATHINFO_EXTENSION);
$student_image_name = 'student_'.$t.'.'.$ext;
$_POST['student_name'] = $student_image_name;
$ftp_server="52.237.5.85";
$ftp_user_name="myservercreds";
$ftp_user_pass="MyServerCreds";
$file = $_FILES['student_image']['name'];//tobe uploaded
$remote_file = "/Students/".$_POST['student_name'];
// set up basic connection
$conn_id = ftp_connect($ftp_server);
// login with username and password
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);
// upload a file
if (ftp_put($conn_id, $remote_file, $file, FTP_ASCII)) {
echo "successfully uploaded $file
";
exit;
} else {
echo "There was a problem while uploading $file
";
exit;
}
// close the connection
ftp_close($conn_id);
}
During debugging I got True and resource everywhere except at one place in a function ftp_put()
.
我想连接到一个远程FTP服务器并将图像文件上传到该服务器的某个特定位置。 我能够连接到服务器但无法上传文件。 p>
每次函数 以下是我的代码: p>
HTML代码: strong> p>
PHP代码(xyz.php): strong> p>
在调试过程中,除了在一个地方,我得到了True和资源 在函数 ftp_put() code>返回false。 我调试了很多代码,但我不知道我在哪里弄错了。 p>
&lt; form method =“post”enctype =“multipart / form-data”action =“xyz.php”&gt;
&lt; input type =“file”name =“student_image”id =“student_image”/&gt;
&lt; / form&gt;
code> pre>
$ t = time();
$ allowed_image_extension = array(“jpg”,“jpeg”,“gif”,“png”,“JPG”,“JPEG”,“GIF”,“PNG”); \ n if(!empty($ _ FILES ['student_image'] ['name'])){
$ ext = pathinfo($ _ FILES ['student_image'] ['name'],PATHINFO_EXTENSION);
$ student_image_name ='student _'。$ t。'。'。$ ext;
$ _POST ['student_name'] = $ student_image_name;
$ ftp_server =“52.237.5.85”;
$ ftp_user_name =“myservercreds”;
$ ftp_user_pass =“MyServerCreds”;
$ file = $ _FILES ['student_image'] ['name']; //上传
$ remote_file =“/ Student /".$_POST['student_name' ]。
//设置基本连接
$ conn_id = ftp_connect($ ftp_server);
//使用用户名和密码登录
$ login_result = ftp_login($ conn_id,$ ftp_user_name,$ ftp_user_pass);
//上传文件
if(ftp_put($ conn_id,$ remote_file,$ file,FTP_ASCII)){
echo“已成功上传$ file
”;
退出;
} else {
echo“上传$ file时出现问题
”;
退出;
}
//关闭连接
ftp_close($ conn_id);
}
code> pre>
ftp_put() code>中。 p>
div>
You're using the wrong filename:
$file = $_FILES['student_image']['name'];//tobe uploaded
^^^^^^^^
That is the filename of the file on the USER's computer. PHP doesn't use that. It puts the upload into a random file name, and stores that name in ['tmp_name']
. You want
$file = $_FILES['student_image']['tmp_name'];
instead. Since you're using the wrong filename, a file which DOESN'T exist on the server, ftp_put is properly returning false since that non-existent file can't be read.
I believe this is likely due to you passing an absolute path as the $remote_file. A failure on ftp_put should mean you can not write to that location, for whatever reason. I believe changing this so that it does not have the / before the path should fix the issue (note that the file will be relative to the ftp user's home dir, which is typically the directory that you are first displayed when you connect via ftp).
This should look like this:
$file = $_FILES['student_image']['tmp_name'];
$remote_file = "Students/".$_POST['student_name'];
EDIT: Edited answer to include tmp_name instead of name, this is a two-parter.
also why don't you try to get the ftp errors:
$trackErrors = ini_get('track_errors');
ini_set('track_errors', 1);
if (!@ftp_put($my_ftp_conn_id, $tmpRemoteFileName, $localFileName, FTP_BINARY)) {
// error message is now in $php_errormsg
$msg = $php_errormsg;
ini_set('track_errors', $trackErrors);
throw new Exception($msg);
}