求SQL语句 合并重复记录,并累加其中一个字段的值,该如何解决

求SQL语句 合并重复记录,并累加其中一个字段的值
求SQL语句 合并重复记录,并累加其中一个字段的值
a b c d e
0 1/26/2011 70 501262720 峨山县福兴副食品批发部 232256959 70 23225695970
2 1/26/2011 70 501262720 峨山县福兴副食品批发部 232256959 70 23225695970
5 1/26/2011 70 501262720 峨山县福兴副食品批发部 232256959 70 23225695970
125 1/26/2011 70 501262720 峨山县福兴副食品批发部 232256959 70 23225695970

字段E是ID但没有设置主键,我希望通过ID将重复的记录找出来并累积A列的值,形成一条记录,谢谢。

------解决方案--------------------
select b,c,d,e,sum(a)a
from tb
group by b,c,d,e
------解决方案--------------------
SQL code
/*
标题:按某字段合并字符串之一(简单合并)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-06
地点:广东深圳

描述:将如下形式的数据按id字段合并value字段。
id    value
----- ------
1     aa
1     bb
2     aaa
2     bbb
2     ccc
需要得到结果:
id     value
------ -----------
1      aa,bb
2      aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
*/
--1、sql2000中只能用自定义的函数解决
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go

create function dbo.f_str(@id varchar(10)) returns varchar(1000)
as
begin
  declare @str varchar(1000)
  select @str = isnull(@str + ',' , '') + cast(value as varchar) from tb where id = @id
  return @str
end
go

--调用函数
select id , value = dbo.f_str(id) from tb group by id

drop function dbo.f_str
drop table tb


--2、sql2005中的方法
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go

select id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '')
from tb
group by id

drop table tb


--3、使用游标合并数据
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
declare @t table(id int,value varchar(100))--定义结果集表变量
--定义游标并进行合并处理
declare my_cursor cursor local for
select id , value from tb
declare @id_old int , @id int , @value varchar(10) , @s varchar(100)
open my_cursor
fetch my_cursor into @id , @value
select @id_old = @id , @s=''
while @@FETCH_STATUS = 0
begin
    if @id = @id_old
       select @s = @s + ',' + cast(@value as varchar)
    else
      begin
        insert @t values(@id_old , stuff(@s,1,1,''))
        select @s = ',' + cast(@value as varchar) , @id_old = @id
      end
    fetch my_cursor into @id , @value
END
insert @t values(@id_old , stuff(@s,1,1,''))
close my_cursor
deallocate my_cursor

select * from @t
drop table tb

------解决方案--------------------
SQL code
select sum(a) as a,max(b),max(c),max(d),e from 表
where e in 
(select e from 表 group by e having count(*)>1)
group by e