帮忙看一下这个统计整数number中数字digit的个数的程序哪有有关问题啊多谢呦
帮忙看一下这个统计整数number中数字digit的个数的程序哪有问题啊~~谢谢呦
#include <stdio.h>
int main( )
{
int ri,repeat;
int count;
long in;
int countdigit(long number, int digit);
scanf( "%d ",&repeat);
for(ri=1;ri <=repeat;ri++){
scanf( "%ld ",&in);
count=countdigit(in,2);
printf( "count=%d\n ",count);
}
}
int countdigit(long number, int digit)
{
int a,t,count,count1,i;
count=1; count1=0;
while((t=number/10)!=0)
count++;
for(i=1;i <=count;i++)
{a=number;
for(;a> 0;a/=10)
{if(a%10==2)
count1++;}}
return count1;}
------解决方案--------------------
while((t=number/10)!=0)
count++;
//死循環
#include <stdio.h>
int main( )
{
int ri,repeat;
int count;
long in;
int countdigit(long number, int digit);
scanf( "%d ",&repeat);
for(ri=1;ri <=repeat;ri++){
scanf( "%ld ",&in);
count=countdigit(in,2);
printf( "count=%d\n ",count);
}
}
int countdigit(long number, int digit)
{
int a,t,count,count1,i;
count=1; count1=0;
while((t=number/10)!=0)
count++;
for(i=1;i <=count;i++)
{a=number;
for(;a> 0;a/=10)
{if(a%10==2)
count1++;}}
return count1;}
------解决方案--------------------
while((t=number/10)!=0)
count++;
//死循環