高分！SQL语句，动态求时间差

高分求助！SQL语句，动态求时间差
在SQL数据表中有数据：
Date_Time Number
2012-1-7 02:05:57 3
2012-1-7 03:38:52 13
2012-1-7 04:17:07 7
2012-1-7 04:48:32 5
2012-1-7 09:18:34 9
2012-1-7 11:27:55 10
2012-1-7 11:55:38 1
2012-1-7 16:47:56 1
2012-1-7 17:14:37 11
2012-1-7 18:38:02 6
2012-1-7 19:14:04 4
2012-1-7 23:24:13 12
2012-1-7 23:53:45 16
2012-1-8 02:31:22 3
2012-1-8 04:04:34 13
2012-1-8 04:40:32 7
2012-1-8 05:13:03 5
2012-1-8 09:54:32 15
2012-1-8 10:15:32 9
2012-1-8 11:45:17 8
2012-1-8 12:17:26 10
2012-1-8 14:08:11 2
2012-1-8 14:12:39 7
2012-1-8 14:40:15 3
2012-1-8 17:11:52 1
2012-1-8 17:39:49 11
2012-1-8 19:05:55 6
2012-1-8 19:42:22 4
2012-1-8 23:48:32 12

sql查询特定的数据如查询 2012-1-7 9:00:00到2012-1-8 8:00:00
Number值，与上一个时间的时间差，一般周期大概是25h，但是还是有特殊情况
想得出结果= Number值,时间差1，时间差2
sql语句如何处理呢？请教高手！！！！

------解决方案--------------------

探讨
抱歉本来改好格式重新上传的，您回复了，不能生成修改。见谅哈

引用:
没看明白

------解决方案--------------------

SQL code


--没有看明白...是不是这样一个思路
;with cte as
(
select rownumber() over(order by date_time) as sn,date_time,number from tb
)
select a.date_time,a.number,datediff(hh,a.date_time,b.date_time) as difftime,(b.number-a.number) as number_diff from cte as a join cte as b  on a.sn=b.sn+1
--没有在分析器里写..因为我不懂你的思路.不知道写的对不对..大致就这个思路

------解决方案--------------------

SQL code



IF OBJECT_ID('tempdb..#FF') IS NOT NULL
DROP TABLE #FF 
GO
CREATE TABLE #FF (Number INT,Date_Time DATETIME)

INSERT #FF
SELECT 1,'2012-1-7 02:05:57' UNION ALL
SELECT 2,'2012-1-7 03:38:52' UNION ALL
SELECT 4,'2012-1-7 04:17:07' UNION ALL
SELECT 3,'2012-1-7 04:48:32' UNION ALL
SELECT 2,'2012-1-7 09:18:34' UNION ALL
SELECT 1,'2012-1-7 11:55:38' UNION ALL
SELECT 1,'2012-1-7 16:47:56' 

DECLARE @NUMBER INT,@QSSJ DATETIME,@JZSJ DATETIME
SELECT @NUMBER = 1,@QSSJ = '2012-1-7 9:00:00',@JZSJ = '2012-1-8 8:00:00'

SELECT 
A.Number,
A.Date_Time,
B.Date_Time,
'分钟相差' = CAST(DATEDIFF(hh,B.Date_Time,A.Date_Time) AS VARCHAR(5)) 
            +'小时'+CAST(DATEDIFF(mi,B.Date_Time,A.Date_Time)%60 AS VARCHAR(10))+'分'
            +CAST(DATEDIFF(ss,B.Date_Time,A.Date_Time)%60 AS VARCHAR(10))+'秒'
 
FROM (
SELECT Number = MAX(Number),Date_Time = MAX(Date_Time),ROW = 0 FROM #FF WHERE Date_Time < @QSSJ AND Number = 1
UNION ALL
SELECT Number,Date_Time,ROW = ROW_NUMBER() OVER(ORDER BY(Date_Time ) ) FROM #FF WHERE Date_Time BETWEEN @QSSJ AND @JZSJ AND Number = 1
    ) A 
JOIN 
(
SELECT Number = MAX(Number),Date_Time = MAX(Date_Time),ROW = 0 FROM #FF WHERE Date_Time < @QSSJ AND Number = 1
UNION ALL
SELECT Number,Date_Time,ROW = ROW_NUMBER() OVER(ORDER BY(Date_Time ) ) FROM #FF WHERE Date_Time BETWEEN @QSSJ AND @JZSJ AND Number = 1
    ) B ON A.ROW = B.ROW+1
/*

Number      Date_Time               Date_Time               时间相差
----------- ----------------------- ----------------------- ---------------------------------
1           2012-01-07 11:55:38.000 2012-01-07 02:05:57.000 9小时50分41秒
1           2012-01-07 16:47:56.000 2012-01-07 11:55:38.000 5小时52分18秒

*/

------解决方案--------------------

SQL code


DECLARE @NUMBER INT,@QSSJ DATETIME,@JZSJ DATETIME
SELECT @NUMBER = 1,@QSSJ = '2012-1-7 9:00:00',@JZSJ = '2012-1-8 8:00:00'

SELECT 
A.Number,
A.Date_Time,
B.Date_Time,
'时间相差' = CAST(DATEDIFF(hh,B.Date_Time,A.Date_Time) AS VARCHAR(5)) 
            +'小时'+CAST(DATEDIFF(mi,B.Date_Time,A.Date_Time)%60 AS VARCHAR(10))+'分'
            +CAST(DATEDIFF(ss,B.Date_Time,A.Date_Time)%60 AS VARCHAR(10))+'秒'
 
FROM (
SELECT Number = MAX(Number),Date_Time = MAX(Date_Time),ROW = 0 
FROM #FF WHERE Date_Time < @QSSJ AND Number = @NUMBER
UNION ALL
SELECT Number,Date_Time,ROW = ROW_NUMBER() OVER(ORDER BY(Date_Time ) ) 
FROM #FF WHERE Date_Time BETWEEN @QSSJ AND @JZSJ AND Number = @NUMBER
    ) A 
JOIN 
(
SELECT Number = MAX(Number),Date_Time = MAX(Date_Time),ROW = 0 
FROM #FF 
WHERE Date_Time < @QSSJ AND Number = @NUMBER
UNION ALL
SELECT Number,Date_Time,ROW = ROW_NUMBER() OVER(ORDER BY(Date_Time ) ) 
FROM #FF 
WHERE Date_Time BETWEEN @QSSJ AND @JZSJ AND Number = @NUMBER
    ) B ON A.ROW = B.ROW+1
/*上面参数@NUMBER忘记放里面了*/

高分！SQL语句，动态求时间差

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