HDU1051-Wooden Sticks
HDU1051--Wooden Sticks
Total Submission(s): 11070 Accepted Submission(s): 4553
Wooden Sticks
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11070 Accepted Submission(s): 4553
Problem Description
There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick.
The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.
You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.
You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).
Input
The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden sticks in the test case,
and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.
Output
The output should contain the minimum setup time in minutes, one per line.
Sample Input
3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1 1 2 2 3 1 3 2 2 3 1
Sample Output
2 1 3
解析:简单的贪心问题,但是有点非常容易错误,每个stick只能减免一个的stick的执行时间,所以每次的数据需要更新,方法直接排序,可以按照长度或者重量排序都可以,对每个stick进行标记看是否执行过,然后从头开始遍历,对于每个stick看能减肥几个,没减免一个就需要更新其比较的长度或者重量,如果还是不清楚的话,可以看我的代码哈!
贴一下自己的代码哈!
#include<iostream> #include <algorithm> using std::endl; using std::cin; using std::cout; using std::sort; const int MAXN = 5000 + 200; struct stick{ int length; int weight; //标记是否访问过 int tag; }sticks[MAXN]; //排序函数 bool cmp(stick a , stick b) { if(a.length > b.length) return true; if(a.length == b.length) return a.weight > b.weight; return false; } int main() { #ifdef LOCAL freopen("input.txt" , "r" , stdin); #endif int T; cin >> T; while(T--) { int n; cin >> n; for(int i=0; i<n; ++i) { cin >> sticks[i].length >> sticks[i].weight; sticks[i].tag = 0; } sort(sticks , sticks+n , cmp); int time = 0 , weight; for(int i=0; i<n; ++i) { //对每个未访问过的stick进行遍历 if(!sticks[i].tag) { sticks[i].tag = 1; time++; weight = sticks[i].weight; for(int j=i+1; j<n; ++j) { if(!sticks[j].tag && weight >= sticks[j].weight) { //如果符合条件可以减免然后更新下次比较的重量 weight = sticks[j].weight; //更新访问标记 sticks[j].tag = 1; } } } } cout << time << endl; } return 0; }